需要帮助在手机的默认浏览器打开一个URL [英] Need help opening a url in the phone's default browser

问题描述

我试图让测试程序，按下一个按钮会打开一个网站。我已经做了听众和一切，我的问题就是这样，网址开放脚本，使一个错误，并告诉我：开放的我们解决不了。这里的剧本我用它来打开一个网页：

I'm trying to make test-program that opens a website by pushing a button. I have made a listener and everything, my problem is just that, the url-opening-script makes an error and tells me "Uri cannot be resolved". Here's the script I use to open up an webpage:

Intent browserIntent = new Intent("android.intent.action.VIEW",Uri.parse("http://www.google.com"));  
startActivity(browserIntent);

我有进口android.app.Activity; ，进口android.content.Intent; 和进口android.content.ContentUris; （也许是不需要的最后一个），所以我不能找出什么是错的...

I have the import android.app.Activity;, import android.content.Intent; and import android.content.ContentUris; (maybe the last one isn't needed) so I can't find out what's wrong...

我希望有人知道我做错了，或者忘记导入...

I hope someone knows what I've done wrong, or forgot to import...

P.S。我用这个页面去我所在的地方：

P.S. I've used this pages to get to where I am:

<一个href=\"http://stackoverflow.com/questions/2201917/android-open-url-from-$c$c\">http://stackoverflow.com/questions/2201917/android-open-url-from-$c$c

<一href=\"http://stackoverflow.com/questions/3004515/android-sending-an-intent-to-browser-to-open-specific-url\">http://stackoverflow.com/questions/3004515/android-sending-an-intent-to-browser-to-open-specific-url

推荐答案

导入Uri类。如果您使用的是Eclipse可以按Ctrl-Shift-O组合添加需要进口，并删除未使用的。

Import the Uri class. If you are using Eclipse you can hit ctrl-shift-o to add needed imports, and remove unused ones.

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