Mod10计算? [英] Mod10 Calculation?
问题描述
我需要帮助来尝试生成用于生成MOD10校验位的代码段. 从理论上讲，这很简单，但是由于我是一个全新的人，所以我不确定如何将其转换为C#.
I need help trying to come up with a snippet for generating a MOD10 check digit. In theory it's pretty simple, but I'm not sure how to translate this into C# as I am completely new.
如果我有8位数字，例如12345678，我需要将偶数位置乘以1，将奇数位置乘以2. :
If I have a 8 digit number, say 12345678, I need to multiple the even positions by 1 and the odd by 2. Then I need to take those results and add the digits together, which would break down like this:
1 2 3 4 5 6 7 8
1 2 3 4 5 6 7 8
1 2 1 2 1 2 1 2
1 2 1 2 1 2 1 2
--------------------
--------------------
1 + 4 + 3 + 8 + 5 + 1 + 2 + 7 + 1 + 6(请注意，如果您获得两位数的结果，则必须分别添加两位数)
1+4+3+8+5+1+2+7+1+6 (Keep in mind if you get a double digit result you have to add each digit separately)
我从中得到38，如果您得到38％10，您得出8，而10-8是2，则校验位将为2. 如何将其转换为C#?
I get 38 from that, and if you do 38 % 10 you come up with 8, and 10-8 is 2 therefore the check digit would be 2. How can I translate this into C#?
推荐答案
嗯...显示的步骤是将偶数位置乘以 2 和奇数 1 ".哪一个?
Humm... the steps you shown are "multiply the even positions by 2 and the odd by 1". Which one?
将偶数位置乘以1，将奇数位置乘以2"
With "multiply the even positions by 1 and the odd by 2"
1 2 3 4 5 6 7 8
1 2 3 4 5 6 7 8
2 1 2 1 2 1 2 1
2 1 2 1 2 1 2 1
2 2 6 4106148
2 2 6 4106148
2 + 2 + 6 + 4 + 1 + 0 + 6 + 1 + 4 + 8 = 34
2 + 2 + 6 + 4 + 1 + 0 + 6 + 1 + 4 + 8 = 34
34 mod 10 = 4
34 mod 10 = 4
应该是这样的:
string a = "12345678";
List<char> result = new List<char>();
for (int i = 0; i < a.Length; i++)
{
result.AddRange(Convert.ToString((Convert.ToInt32(a[i]) - 48) * (i % 2 == 1 ? 1 : 2 )));
}
Console.WriteLine(10 - result.Select(x => Convert.ToInt32(x)).Sum() % 10);
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