PHP Time()函数在C ++中 [英] Php time() function in c++

问题描述

你好，我只是想通过调用time()来获得一个等于在php中生成的值.

这是由php生成的:1353963208650

而这个由c ++编写:1353963158

它们相等，但是以某种方式，c ++值仅为4个字节.最后4个字节为空，但我需要一个等于100％的值.我的代码atm:

Hello I just tried to get a value which equals to the one which is generated in php by calling time().

This one was generated by php: 1353963208650

And this one by c++ : 1353963158

They equal but somehow the c++ value is just 4 bytes. The last 4 bytes are nulled,but I need a value which equals 100%. My Code atm:

time_t seconds = time(NULL);
printf("PHP-Time: %ld\n",seconds);

推荐答案

您是如何得到结果的?
我的测试:
(输出)

How did you get your results?
My test:
(output)

>
1353965820(C ++)
1353965860(PHP)

1353965820 (C++)
1353965860 (PHP)

(当然，它们是有所不同的，因为它们是在不同的时间执行的)

(程序)

(of course they differ a bit, because were executed at different times)

(programs)

#include <iostream>
#include <ctime>
using namespace std;
int main()
{
  cout << time(NULL) << endl;
  return 0;
}

<?php 
echo time();
 ?>

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