使用C ++帮助指针和字符； [英] Help Pointers and chars in C++;

问题描述

嘿.当我这样做时:
char * suit ="Hearts"; cout<< *西装;它印有Hearts；

但是在这种情况下:仅打印"m".为什么?

Hey.When I do this:
char *suit = "Hearts"; cout<<*suit; it prints Hearts;

But in this case: It is only printing "m". WHY?

#include "stdafx.h"
#include <iostream>
using namespace std;

class yup{
public:
	yup(char *);
	void print();
private:
	char *name;
};
yup::yup(char *x)
{
	name = x;
}
void yup::print()
{
	cout<<*name;
	cout<<endl;
}
int _tmain(int argc, _TCHAR* argv[])
{
	yup t("missak");
	t.print();
	return 0;
}

推荐答案

在这里，您仅将x的地址分配给名称.并且x的地址是"missak"的"m".

Here you are only assigning the adress of x into name. And at the adress of x is the ''m'' of "missak".

yup::yup(char *x)
{
	name = x;
}

在此打印地址名称"的内容.内容是一个字符.是字母"m".

Here the content of the adress "name" is printed. And the content is a single char. It''s the letter ''m''.

void yup::print()
{
    cout<<*name;
    cout<<endl;
}

您必须将整个字符串复制到您的私有成员中.
在C中，您可以这样操作，例如

You have to copy the whole string into your private member.
In C you could do this like this e.g.

char szName[BUFF_SIZE];

void yup(const char *x)
{
   if( strlen(x) < BUFF_SIZE )
   {
      strcpy(szName, x);
   }

}

在C ++中，还有一个用于字符串的类.我目前在这里没有很好的参考.但是，在Google Project上进行一些Google搜索或搜索将对您有所帮助.

In C++ there is also a class for strings. I don''t have a good reference right here at the moment. But a little google or search on CodeProject will help you..

引用:

cout<< * name;

cout<<*name;

您应该改写

You should write instead

cout << name;

顺便说一句，您不应该存储指向原始字符数组的指针(它可能是临时的).您应该改为复制数组内容.更好的是，您可以使用std::string:

By the way you shouldn''t store a pointer to the original character array (it could be a temporary). You should instead copy the array content. Even better you could use a std::string:

#include "stdafx.h"
#include <iostream>
#include <string>
using namespace std;
class yup{
public:
	yup(char *x ):name(x){};
	void print();
private:
	string name;
};
void yup::print()
{
	cout << name;
	cout << endl;
}
int _tmain(int argc, _TCHAR* argv[])
{
	yup t("missak");
	t.print();
	return 0;
}

当我这样做时:

char *suit = "Hearts"; cout<<*suit;

它印有《心》；

它不应该，它应该只打印字符"H".您要做的是，取消引用指向char的指针，因此它只是一个char.这就是为什么它只是从您的班级打印出来的字符.

如果希望类打印整个字符串，请不要取消引用char指针.

it prints Hearts;

It shouldn''t, it should print the character ''H'' only. What you do is, you dereference the pointer-to-char, so it is only a char. That''s why it''s only the char that is printed from your class.

If you wish the class to print the whole string, don''t dereference the char pointer.

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