waveoutwrite函数将WAVEHDR *复制到设备缓冲区还是将其用作参考? [英] does waveoutwrite function copy WAVEHDR* to device buffer OR it uses it as reference?

问题描述

你好，

我正在使用mmsystem的wavout *函数播放音频.

I am using mmsystem's wavout* functions for audio playback. 

我想在waveOutWrite函数之后立即删除分配的堆.我每次都会为新块分配512 * 16大小的新堆，并且出于内存管理的考虑，我想在waveOutWrite之后将其删除.

I want to delete the allocated heap immediately after waveOutWrite function. I am allocating new heap of 512 * 16 size for new chunk every time and I wanted to delete it after waveOutWrite, for the matter of memory management.

如果我这样做，可以在设备上使用吗?或waveOutWrite将使用我传递给它的waveHdr指针的引用，由于这个原因，我需要等待直到WOM_DONE回调删除分配的缓冲区?

If i do this, will it be ok for device? OR waveOutWrite will use the reference of the waveHdr pointer I have passed to it and due to this I need to wait until WOM_DONE callback to delete allocated buffer? 

我每次都会为新块分配新的堆，以防止急促的音频播放.

I am allocating new heaps each time for new chunks for the purpose of anit-jerk audio playback.

 

谢谢.

推荐答案

无论使用哪种通知机制，您都必须等待驱动程序完成缓冲区的播放.

You must wait until the driver has finished playing the buffer, whatever notification mechanism you use.

分配内存是非常昂贵的操作.每次分配一个新缓冲区都比使用预先分配的缓冲区慢.

Allocating memory is a very expensive operation. Allocating a new buffer each time is going to be slower than using a pool of preallocated buffers.

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