不接受小数作为输入的计算器 [英] Calculator that does not accept decimals as input

问题描述

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace Accessible_Calculater
{
    class Program
    {
        private static object e;
        private static int num1;

        public static string Keypressed { get; private set; }
        public static object Keys { get; private set; }
        public static object Answer { get; private set; }

        static void Main(string[] args)
        {
            while (true)
            {

                 int num1;
                int num2;
                string operand;
                 float answer;
                Console.Write("Please enter the first integer: ");
                num1 = Convert.ToInt32(Console.ReadLine());
                Console.Write("Please enter an operand (+, -, /, *): ");
                operand = Console.ReadLine();
                Console.Write("Please enter the second integer: ");
                num2 = Convert.ToInt32(Console.ReadLine());
                switch (operand)
                {
                    case "-":
                        answer = num1 - num2;
                        break;
                    case "+":
                        answer = num1 + num2;
                        break;
                    case "/":
                        answer = num1 / num2;
                        break;
                    case "*":
                        answer = num1 * num2;
                        break;
                    default:
                        answer = 0;
                        break;
                }
                Console.WriteLine(num1.ToString() + " " + operand + " " + num2.ToString() + " = " + answer.ToString());
                Console.ReadLine();
            }
        }
    }
}

推荐答案

你好

我建议您将输入的String转换为Decimal类型的对象.

 I suggest you convert the input String to Decimal type object.

由于Int类型无法处理十进制值.另外，请注意，

As Int types can not handle decimal values.  Also, as a note,

您正在使用无限的While(true)循环.重新编码出口

you are using While(true) loop that is infinite.  ReCode an exit

打破循环.例如，如果String == Null，则Break

to break the loop. Such as, If String == Null then Break

希望有帮助. :)

这篇关于不接受小数作为输入的计算器的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！