定量阿匹特德百分比问题 [英] quantative apitutde percentage problems

问题描述

在一个城镇的1000个人口中，有60％是男性，其中20％是有文化的.如果在所有人口中，有25％的人是识字的，那么女性中百分之几的人是识字的

解决方案

这似乎不是编程问题.这是一个简单的数学问题.可能是这样的:

  double  maleLiterateFraction =( 60 / 20 ///  60％* 20％
 double  femaleLiterateFraction =  0 . 25 -maleLiterateFraction ; //  25％-(男性识字率)
 double  femaleLiteratePercent = femaleLiterateFraction *  100 ; // 将分数转换为百分比 

有关百分比的更多信息，请参见: http://www.mathsisfun.com/percentage.html [ ^ ].

Of the 1000 of population of a town, 60%are males of whom 20% are literate. If of all the population 25% are literate , the what percent of the female of the are literate

解决方案

It doesn''t seem like a programming problem. It''s a simple math problem. It can be something like:

double maleLiterateFraction = (60 / 100) * (20 / 100); // 60% * 20%
double femaleLiterateFraction = 0.25 - maleLiterateFraction; // 25% - (male's literate percent)
double femaleLiteratePercent = femaleLiterateFraction * 100; // Convert fraction to percents

For more information about percentages see: http://www.mathsisfun.com/percentage.html[^].

这篇关于定量阿匹特德百分比问题的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！