如何有条件地读取所有属性? [英] How to read all attributes conditionally?

问题描述

我想使用where子句读取所有可枚举的属性.

I want to read all attributes as I Enumerable using where clause.

所以我想要的是将Employee返回为List，其中List = PayList

So what I want is return Employee as List where List = PayList

下面是我的XML.

<Employees Table="ListColumns" StartAt="1" Output="Return">
  <Lists List="PayList">
    <Employee Start="51" Length="11" Name="Amount"/>
    <Employee Start="62" Length="6" Name="Name"/>
    <Employee Start="68" Length="50" Name="Reason"/>
    <Employee Start="118" Length="7" Name="Action"/>
    <Employee Start="125" Length="6" Name="First"/>
    <Employee Start="131" Length="6" Name="Last"/>
    <Employee Start="137" Length="40" Name="Payee"/>
    <Employee Start="177" Length="6" Name="Banker"/>
    <Employee Start="183" Length="19" Name="DateIssued"/>
    <Employee Start="202" Length="19" Name="DateStopped"/>
  </Lists>
  <Lists List="ResponseList">
    <Employee Start="51" Length="11" Name="Amount"/>
    <Employee Start="62" Length="6" Name="Name"/>
    <Employee Start="68" Length="50" Name="Reason"/>
    <Employee Start="118" Length="7" Name="Action"/>
    <Employee Start="125" Length="6" Name="First"/>
    <Employee Start="131" Length="6" Name="Last"/>
    <Employee Start="137" Length="40" Name="Payee"/>
    <Employee Start="177" Length="6" Name="Banker"/>
    <Employee Start="183" Length="19" Name="DateIssued"/>
    <Employee Start="202" Length="19" Name="DateStopped"/>
  </Lists>
</Employees>

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Ashwani Vashishtha

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Ashwani Vashishtha

推荐答案

    var lists = from ls in XDocument.Load(@"C:\TEMP\Employee.xml").Descendants("Lists")
                        where ls.Attribute("List").Value == "PayList"
                        select ls;

            var employees = from emp in lists.Descendants("Employee")
                            select new Employee
                            {
                                Start = emp.Attribute("Start").Value,
                                Length = emp.Attribute("Length").Value,
                                Name = emp.Attribute("Name").Value
                            };

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