查找符合条件的字符? [英] Find characters in line?

问题描述

我有一条类似"kjhdjhdah @ lddhfdj"的行.您能给我伪代码在行中找到@符号吗?

I had a line like "kjhdjhdah@lddhfdj".Can you please give me pseudo code to find @ symbol in the line?

推荐答案

开始此处 [此处 [ ^ ]并花费有一段时间学习.如果您想了解如何操作字符串中的字符，请在库部分中找到std :: string的条目，并检查所有可用的方法；否则，请参见.可能会有一个叫做 find() [

Start here[^] and here[^] and spend some time studying. If you want to find out how to manipulate characters within strings then find the entry for std::string in the library section and check all the available methods; there will probably be one called find()[^]. You should really get familiar with the MSDN documentation, as I have suggested to you in a number of your previous questions.

使用strchr()函数.

Use strchr() function.

char *strchr(
   const char *string,
   int c 
);
);

返回指向字符串中第一次出现c的指针；如果找不到c，则返回NULL. 对于Unicode版本，可以使用wcschr.

Returns a pointer to the first occurrence of c in string, or NULL if c is not found.
For Unicode version, wcschr can be used.

使用

char * strchr ( const char *, int ); 

考虑下面的示例.

consider the example below.

/* strchr example */
#include <stdio.h>
#include <string.h>

int main ()
{
    char str[] = "This is a sample string";
    char * pch;
    printf ( "Looking for the 's'character in \"%s\"...\n", str );
    pch = strchr(str,'s' );
    while ( pch != NULL )
    {
        printf ( "found at %d\n", pch - str + 1 );
        pch = strchr( pch + 1, 's' );
    }
   return 0;
}</string.h></stdio.h>

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