如何获取WCF Restful Service的ref或out参数? [英] How to get the ref or out parameter of WCF Restful Service?

问题描述

我有一个WCF Restful Service，如下所示:

I have a WCF Restful Service, like below:

        [OperationContract]
        [WebInvoke(Method ="POST", BodyStyle = WebMessageBodyStyle.Wrapped, RequestFormat =WebMessageFormat.Json,
           ResponseFormat = WebMessageFormat.Json, UriTemplate = "CPSendInfo")]       
        int COSendTubeInfo(List<CPTXInfo> LstData,out string ErrMsg);

我想通过我的方法获得ErrMsg.怎么办?

I want get the ErrMsg by my method. How to do?

谢谢.有人可以尽快给我答复吗?

Thanks. Can some one reply me as soon as possible?

最紧急！！！

再次感谢.

Vince

推荐答案

Vince，

Hi Vince,

您想得到Ajax的回复吗?如果尝试使用Fiddler或PostMan发送请求，则会收到如下所示的响应，并且可以检索json对象.

Did you want to get response from Ajax? If you try Fiddler or PostMan to send request, you will get response like below, and you could retrieve the json object.

{
  "COSendTubeInfoResult": 123,
  "ErrMsg": "Error"
}

这是一个简单的演示，可让Ajax获得响应.

Here is a simple demo for getting response by Ajax.

//WCF Rest Service
//IService
        [OperationContract]
        [WebInvoke(Method = "POST", BodyStyle = WebMessageBodyStyle.Wrapped, RequestFormat = WebMessageFormat.Json,
           ResponseFormat = WebMessageFormat.Json, UriTemplate = "CPSendInfo")]
        int COSendTubeInfo(int LstData, out string ErrMsg);
//Service
        public int COSendTubeInfo(int LstData, out string ErrMsg)            
        {
            ErrMsg = "Error";
            return 123;
        }

//Ajax Request

(function(){ var p = {"LstData":123};

(function () { var p = { "LstData": 123 };

.ajax({ 类型:"POST"， contentType:"application/json; charset = utf-8"， 网址:"http://localhost:39668/RestService.svc/CPSendInfo"， 数据:JSON.stringify(p)， 数据类型:"json"， 成功:功能(数据){ console.log(data.COSendTubeInfoResult); console.log(data.ErrMsg); }， 错误:函数(结果){ 警报(结果); } }); });

.ajax({ type: "POST", contentType: "application/json; charset=utf-8", url: 'http://localhost:39668/RestService.svc/CPSendInfo', data: JSON.stringify(p), datatype:'json', success: function (data) { console.log(data.COSendTubeInfoResult); console.log(data.ErrMsg); }, error: function (result) { alert(result); } }); });

最好的问候，

Best Regards,

爱德华

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