“激活要求应用程序的RunAs值是Activate As Activator".提升VB COM DLL时出现错误 [英] "The activation requires that the RunAs value for the application is Activate As Activator" error while elevating a VB COM dll

问题描述

我有Win32 exe，我正在尝试从中提升COM dll(UTL :: _ RegistryUtils).因为它会写入HKLM位置，所以我不想在提升模式下运行整个应用程序.

类似于以下内容:-
UTL :: _ RegistryUtils * pRegUtils = NULL;
HWND hnd = GetActiveWindow();//(或NULL)
hr = CoCreateInstanceAsAdmin(hn d ，UTL :: CLSID_RegistryUtils，UTL :: IID__RegistryUtils，(void **)& pRegUtils);
if(FAILED(hr)){
> HRESULT CoCreateInstanceAsAdmin(HW ND hwndMain，__in REFCLSID rclsid，__in REFIID riid，__deref_out void ** ppv)
{
MonikerSize + CLSIDSize ];

StringFromGUID2(rclsid，wszCLSID，ARRAYSIZE(wszCLSID));
HRESULT hr = StringCchPrintf(wszMoniker 名称，ARRAYSIZE(wszMonikerName)， MonikerName，wszCLSID);
如果(FAILED(hr))
返回hr; bo，0，sizeof(bo));
bo.cbStruct = sizeof(bo);
bo.hwnd = hwndMain;
bo.dwClassContext = CLSCTX_LOCAL_SERVER;
hr = CoGetObject(wszMonikerName ，&bo，riid，ppv);
/*
此处"hr"获得错误值:"0x80080016激活要求应用程序的RunAs值为激活为激活器"
* /hr;
}

我做了所有注册表设置，例如:
HKEY_LOCAL_MACHINE \ SOFTWAR E \ Classes
{
AppID \ CommonUtils.dll
{
(默认):REG_SZ = null
AppID:REG_SZ ='{6BCFB187-C1DD-4807-96AD- F91AB4AB08 AC}'
}

AppID \ { 6BCFB187-C1DD-4807- 96AD-F91AB 4AB08AC}
{
(默认):REG_SZ ='CommonUtils'
AccessPermission:REG_BINARY = <二进制值> te:REG_SZ =``
}

CLSID \ {6BCFB187-C1DD-4807- 96AD-F91AB 4AB08AC}
{
(默认):REG_SZ =' CommonUtils'
AppID:REG_SZ ='{6BCFB187-C1DD-4807-96AD- F91AB4AB08 AC}'
LocalizedString:REG_SZ ='@C:\您的\路径\此处\公用 Utils.dll， -101'

仰角
{默认值:REG_SZ = null
启用:REG_DWORD = 1
}
}
>}

UTL :: CLSID_RegistryUtils是简单的VB COM dll.我正在VS2008中开发，平台是Vista.

有人可以帮助我解决此错误吗?

推荐答案

您看过吗?

http://blogs.msdn.com/vistacompatteam/archive/2006/09/28/CoCreateInstanceAsAdmin-or-CreateElevatedComObject-sample.aspx

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