如何从图像框中获取白色像素? [英] How to get white pixel from image box?

问题描述

海佬..
我是C#语言的初学者..
我有一个基于大小将水果分类的项目.
这是我的步骤:
1.从网络摄像头捕获图像.
2.将图像转换为灰度.
3.将图像转换为二进制图像.
4.计算白色像素以获取对象大小.

但是现在，我陷入了步骤4..
我无法计算图像框中的白色像素，
我的项目使用C#和emguCV作为库，
有人可以解决我的问题吗?如何计算图像框中的白色像素?
谢谢，
(对不起，我的英语不好:D)

-添加了注释中的格式化代码

这是将图像捕获转换为二进制图像的代码:

Hai guys..
I''m a beginner in C# language..
I have a project to classification fruits based on size..
This is my step :
1. Capture image from webcam.
2. Convert image to gray scale.
3. Convert image to binary image.
4. Counting white pixel to getting the object size.

But now, i get stuck on step 4..
I can''t count white pixel from image box,
My project using C# and emguCV as a library,
Anybody can solve my problem? How to count white pixel from image box?
Thanks,,
(Sorry for my bad English :D)

- Added formatted code from comment

This the code to convert image capture to binary image :

Image<gray,> imgTarget = hueFilter.And(saturationFilter).And(valueFilter);
           imgTarget._Erode(1);
           imgTarget._Dilate(1);
           Image<gray,> bin = imgTarget.ThresholdBinary(new Gray(80), new Gray(255));
           imageBox3.Image = bin.Resize(320, 240, Emgu.CV.CvEnum.INTER.CV_INTER_LINEAR, true);
           imgTarget.Dispose();
           channels[0].Dispose();
           channels[1].Dispose();
           channels[2].Dispose();

但是我尝试使用此代码来计算白色像素值:

But i was try to count the white pixel value using this code :

Image<gray,> binary = new Image<gray,>(320, 240);
imageBox3.Image = binary;

for (int i = 0; i < binary.Rows; i++)
{
    for (int j = 0; j < binary.Cols; j++)
    {

        binary.Data[i, j, 0] = 255;


        byte white = binary.Data[i, j, 0];




        lblWhite.Text = white + " white pixels";
    }

当我运行此项目时，"lblWhite获得值= 255"，但它没有计算白色像素..

And when i run this project the "lblWhite getting value = 255" , but it did''t count the white pixel..
Can you tell me what''s the problem?

推荐答案

首先，图像放大和腐蚀方法使用3x3像素网格，这会影响您的结果，但我认为这是故意的.
我会先使用3x3的白色图像开始，然后对侵蚀，膨胀，阈值和调整大小的操作进行注释.这样，您就有了基线来检查其余的代码.

ImageBox对我来说没有多大意义:最好只使用binary.

您在任何地方都没有比较功能，我希望您将循环中的当前像素与白色像素进行比较，或者将亮度值与255比较.

[edit]
循环的内容对于计算白色像素是错误的，您有两个先行障碍:

Hi, first off the image dilate and erode methods use a 3x3 grid of pixels this will effect your results, but I assume this is deliberate.
I''d start off using a 3x3 white image to start with, and comment the erode, dilate, threshold and re-size operations. That way you have baseline to check the rest of your code.

ImageBox doesn''t make much sense to me: you''d be better off just using binary.

You don''t have comparison anywhere, I''d expect you to compare the current pixel in your loop with a white one, or compare the brightness value with 255.

[edit]
the contents of loop is wrong for counting the white pixels, you have two preoblems:

binary.Data[i, j, 0] = 255; //This sets the pixel to white (I assume)

然后

then

byte white = binary.Data[i, j, 0];

获取刚刚设置为白色(255)的像素的值.


我认为您需要更多类似的东西:

Gets the value of the pixel, which you''ve just set to white (255).


I think you need something more like:

int count = 0;
for (int i = 0; i < binary.Rows; i++)
{
    for (int j = 0; j < binary.Cols; j++)
    {
         if(binary.Data[i, j, 0] == 255)
             count++;
         lblWhite.Text = string.Format("{0} white pixels", count);
    }
}

我发现的一件事是，在任何大小合适的图像中循环像素都是缓慢的，但是您只能优化一种基本算法正在工作的图像.

One thing I''ve found is that looping the pixels in any reasonably sized image is slow, but you should only optimise one your basic algorithm is working.

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