如何使用线程停止此三角动画 [英] how stop this trigonometric animation , using threads

问题描述

<Grid>
      <Canvas Height="202" HorizontalAlignment="Left" Margin="10,97,0,0" Name="MyChart" VerticalAlignment="Top" Width="481" Background="#FFC3EEE3"></Canvas>
      <Button Content="Iniciar" Height="23" Name="buIniciar" Width="75" Margin="10,12,418,276" Click="buIniciar_Click" />
      <Button Content="Detener" Height="23" Name="buDetener" Width="75" Margin="10,45,418,243" Click="buDetener_Click" />
  </Grid>

public partial class MainWindow : Window
    {
        double time = 0;
        Polyline pl;
        TranslateTransform translate;
        ManualResetEvent evtObj = new ManualResetEvent(false);

        public MainWindow()
        {
            InitializeComponent();
        }


        public float ValorFuncion1(double X)
        {
            return Convert.ToSingle(Math.Sin(X));
        }
        public float ValorFuncion2(double X)
        {
            return Convert.ToSingle(Math.Abs(Math.Cos(X)) * Math.Sin(X) + Math.Abs(Math.Sin(X)) * Math.Cos(X));
        }

   
        public void DoAnimate(int i)
        {
            //while (true)
            //{
            if (MyChart.Dispatcher.Thread == Thread.CurrentThread)
                {
                    pl = new Polyline() { Stroke = new SolidColorBrush(Colors.Red), StrokeThickness = 1.5f };
                    translate = new TranslateTransform(0.0, (MyChart.Height / 2.0f));
                    pl.RenderTransform = translate;
                    MyChart.Children.Add(pl);
                    CompositionTarget.Rendering += delegate(object s, EventArgs args)
                    {
                        Double PosX = pl.ActualWidth;
                        if (PosX >= MyChart.Width)
                        {
                            pl.Points.RemoveAt(0);
                            translate.X--;
                        }
                        double x = time * 0.05;
                        double y = Math.Cos(x); 
                        pl.Points.Add(new Point(time, y * 30));
                        time++;
                    };
                }
                else
                {
                    MyChart.Dispatcher.BeginInvoke(System.Windows.Threading.DispatcherPriority.Normal, new Action(() => DoAnimate(i)));
                }


            //    evtObj.WaitOne(1000);
            //}
        }

        private void buIniciar_Click(object sender, RoutedEventArgs e)
        {
            for (int i = 0; i < 1; i++)
            {
                int j = i;
                ThreadStart ts = delegate() { DoAnimate(j); };
                Thread t = new Thread(ts);
                t.Start();
            }
        }

        private void buDetener_Click(object sender, RoutedEventArgs e)
        {
            evtObj.Set();
        }
    }
}

伙计们，不知道我在做什么错，帮我先谢谢你.

Please guys, do not know what I''m doing wrong, help me I thank you in advance

推荐答案

我的解决方法如下:

为委托创建函数，而不要创建任何函数

My soulution is as follows:

Create a function for the delegate instead of anynymous

private void doDelegate(object s, EventArgs args)
                   {
                       Double PosX = pl.ActualWidth;
                       if (PosX >= MyChart.Width)
                       {
                           pl.Points.RemoveAt(0);
                           translate.X--;
                       }
                       double x = time * 0.05;
                       double y = Math.Cos(x);
                       pl.Points.Add(new Point(time, y * 30));
                       time++;
                   }

然后将其分配给线程

Then assign it to the thread

CompositionTarget.Rendering += doDelegate;

然后更换定位器

Then change the detener

private void buDetener_Click(object sender, RoutedEventArgs e)
        {
           CompositionTarget.Rendering -= doDelegate;
        }

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