关于此功能的简化 [英] Simplification Regarding This Function

问题描述

function ConvertDate(dateString) {
    var datet;
    if (dateString != undefined) {

        var date = new Date(parseInt(dateString.replace(/\/Date\((\d+)\)\//, '$1')));
        var month = date.getMonth() + 1;
        if (month < 10)
            month = '0' + month;
        var day = date.getDate();
        if (day < 10)
            day = '0' + day;
        var year = date.getFullYear();
        var datet = month + "/" + day + "/" + year;
        return datet;
    }
    else {
        datet = String.empty();
        return false;
    }

}

它工作正常，但我想问问是否有人可以对其进行优化或提供替代方法.

It works fine but i wanted to ask if someone could optimize it or provide an alternative.

推荐答案

1'))))); var month = date.getMonth()+ 1 ; 如果(月< 10 ) month = ' 0' + month; var day = date.getDate(); 如果(天< 10 ) day = ' 0' +天； var year = date.getFullYear(); var datet = month + " +天+ " +年； 返回日期； } 其他 { datet = 字符串 .empty(); 返回 假； } }

1'))); var month = date.getMonth() + 1; if (month < 10) month = '0' + month; var day = date.getDate(); if (day < 10) day = '0' + day; var year = date.getFullYear(); var datet = month + "/" + day + "/" + year; return datet; } else { datet = String.empty(); return false; } }

它工作正常，但我想问问是否有人可以优化它或提供替代方法.

It works fine but i wanted to ask if someone could optimize it or provide an alternative.

一个简单的规范可能会更有帮助，但是我怎么看，您想要格式化日期.
您可以使用以下JQuery插件: http://archive.plugins.jquery.com/project/jquery-dateFormat [ ^ ]

A simple specification would have been more helpful, but how I see, you want to format a date.
You can use this JQuery plugin: http://archive.plugins.jquery.com/project/jquery-dateFormat[^]

function ConvertDate(dateString) {
    if (dateString &&

.trim(dateString)！= " "){ 返回

.trim(dateString) != "") { return

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