绝对坐标机器人位图 [英] Absolute coordinates bitmap android
问题描述
我有一个位图,大小比屏幕更大(即,1000×1000)。此位图的感谢,我可以拖到画布上。如果我在点(500,500)的getX或鸵鸟政策的getY返回500否则为0和320的屏幕尺寸模拟器]之间的一些价值,所以我需要知道关于绝对值指向0。我希望我的视图不转换位图比视图的0左和0前点多了。
I have a bitmap with a size greater than screen (i.e, 1000x1000). I can drag this bitmap thanks to canvas. If i am in the point (500,500) getX or getY don´t return 500 else some value between 0 and 320[screen size emulator], so I need to know the absolute value with respect to point 0. I want my View not to translate the bitmap more than the 0 Left and 0 Top points of the View
我把一些code,以澄清问题
I put some code to clarify the question
public MapaView(Context context, AttributeSet attrs) {
super(context, attrs);
mScaleDetector = new ScaleGestureDetector(context, new ScaleListener());
mSurfaceHeight = 640;
mSurfaceWidth = 480;
mapaActual = new Mapa();
mContext = context;
mBufferedCanvas = new Canvas();
}
draw(Canvas c){
bitmapAux.eraseColor(Color.WHITE);
/*draw the rectangles....*/
c.translate(mPosX, mPosY);
c.scale(mScaleFactor, mScaleFactor);
c.drawBitmap(bitmapAux, 0, 0, null);}
我得到下一个方法的位置
I get the position with next method
@Override
public boolean onTouchEvent(MotionEvent ev) {
// Let the ScaleGestureDetector inspect all events.
mScaleDetector.onTouchEvent(ev);
final int action = ev.getAction();
switch (action & MotionEvent.ACTION_MASK) {
case MotionEvent.ACTION_DOWN: {
startTime = ev.getEventTime();
final float x = ev.getX();
final float y = ev.getY();
final float xR= ev.getRawX();
final float yR= ev.getRawY();
movido=false;
mLastTouchX = x;
mLastTouchY = y;
mLastTouchXRaw = xR;
mLastTouchYRaw = yR;
mActivePointerId = ev.getPointerId(0);
break;
}
case MotionEvent.ACTION_MOVE: {
final int pointerIndex = ev.findPointerIndex(mActivePointerId);
final float x = ev.getX(pointerIndex);
final float y = ev.getY(pointerIndex);
// Only move if the ScaleGestureDetector isn't processing a gesture.
if (!mScaleDetector.isInProgress()) {
final float dx = x - mLastTouchX;
final float dy = y - mLastTouchY;
mPosX += dx;
mPosY += dy;
movido=true;
invalidate();
}
mLastTouchX = x;
mLastTouchY = y;
movido=true;
break;
}
case MotionEvent.ACTION_UP: {
mActivePointerId = INVALID_POINTER_ID;
endTime = ev.getEventTime();
if ((endTime - startTime > 500)&&!movido) {
// we have a 1000ms duration touch
// propagate your own event
Log.d("LC", "time touched greater than 1000ms " + endTime + " "
+ startTime);
startTime = 0;
endTime = 0;
movido=false;
Box pepeBox=new Box();
pepeBox=buscarElemento();
//Intent intent=new Intent(mContext,OpcionesConceptoList.class);
//mContext.startActivity(intent);
/*
* return true; notify that you handled this event (do not
* propagate)
*/
}
break;
}
case MotionEvent.ACTION_CANCEL: {
mActivePointerId = INVALID_POINTER_ID;
break;
}
case MotionEvent.ACTION_POINTER_UP: {
final int pointerIndex = (ev.getAction() & MotionEvent.ACTION_POINTER_INDEX_MASK) >> MotionEvent.ACTION_POINTER_INDEX_SHIFT;
final int pointerId = ev.getPointerId(pointerIndex);
if (pointerId == mActivePointerId) {
// This was our active pointer going up. Choose a new
// active pointer and adjust accordingly.
final int newPointerIndex = pointerIndex == 0 ? 1 : 0;
mLastTouchX = ev.getX(newPointerIndex);
mLastTouchY = ev.getY(newPointerIndex);
mActivePointerId = ev.getPointerId(newPointerIndex);
}
break;
}
}
return true;
}
任何意见?
在此先感谢,并请原谅我的英语水平。
Thanks in advance and excuse my english.
推荐答案
getRawX()和getRawY():坐标(X,Y)相对返回手机屏幕
getRawX() and getRawY() : return the coordinate(X,Y) relative to the screen of the phone
的getX()和的getY():返回coordiantes(X,Y)相对于视图
getX() and getY() : return the coordiantes(X,Y) relative to the View.
是什么?其实绝对坐标
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