regex =>在两个匹配项之间提前查找c# [英] regex=>lookahead between two matches c#

问题描述

const string numericReg = "\\d+"; // Matches a digit character. Equivalent to [0-9].
const string realNumsReg = numericReg + b + "(\\." + b + numericReg + ")?";
        const string b = "\\s*";

这个说法是正确的:

This statement is true :

private const string rte = "(?<rate>" + realNumsReg + ")" +
                          "(?=(?<rte1>" + b + "qs " + "))";

和

这个说法是正确的:

and

This statement is true :

private const string barl = "(?<barl>" + numericReg + ")" +
                                   "(?=((?<q>" + b + "point to print )))";

这对于rte是正确的:

this is true for rte :

MatchCollection s = Regex.Matches
                ("3000 qs / min", rte , RegexOptions.IgnoreCase);

这对于barl是正确的:

this is true for barl:

MatchCollection s = Regex.Matches
                ("6 point to print  ", barl , RegexOptions.IgnoreCase);

为什么错了?

Why is this wrong?

MatchCollection s = Regex.Matches
               ("6 point to print  3000 qs/ min", barl+b+rte  , RegexOptions.IgnoreCase);

推荐答案

将此模式与ExplicitCapture作为选项一起使用:
\b*(?<points>\d{1}) point to print (?<qs>\d{1,4})\b</qs></points>

结果-> 2个匹配项:6和3000

是您要找的吗?

Use this pattern with ExplicitCapture as an option:
\b*(?<points>\d{1}) point to print (?<qs>\d{1,4})\b</qs></points>

Result -> 2 matches: 6 and 3000

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