仅使用for循环形成*模式 [英] forming * patterns using only for loops

问题描述

连续三角形的先前版本已完成，并且如果对菱形等四个方向的图形有适当的帮助.

the previous version of consecutive triangles is done and if any help on figures in four directions like rhombus in proper order.

推荐答案

以下是C的一些示例-您可以轻松地将它们移植到.NET:
http://www.interviewmantra.net/2009/10/10-star-pattern- program.html [^ ]

Here are some samples for C - you may easily port them to .NET:
http://www.interviewmantra.net/2009/10/10-star-pattern-programs.html[^]

最喜欢的作业主题之一
``*''模式程序就像拼图一样，喜欢解决它.
一些参考如下
http://forum.notebookreview.com/programming-homework-questions/370222-simple-star-pattern-c.html [ ^ ]
http://www.softwareandfinance.com/CSharp/Loops_Diamond_Pattern.html [ http://www.csharphub.com/2011/03/how-to-write-c-program-to-print-star.html [

One of the Favorite homework topics
''*'' pattern programs are like puzzles so, enjoy solving it.
some references as below
http://forum.notebookreview.com/programming-homework-questions/370222-simple-star-pattern-c.html[^]
http://www.softwareandfinance.com/CSharp/Loops_Diamond_Pattern.html[^]
http://www.csharphub.com/2011/03/how-to-write-c-program-to-print-star.html[^]
Happy Coding!
:)

hiii，

我认为这会帮助您

hiii,

i think this one will help you

class Program
    {
        static void Main(string[] args)
        {
            int i, j, k, n;

            Console.Write("Enter the No. :");
            n = int.Parse(Console.ReadLine());

            for (i = 1; i <= n + (n - 1); i++)
            {
                for (j = 1; j <= n + (n - 1); j++)
                {
                    if (i + j == (n + 1) || i + j == (n + n + n - 1) || i - j == (n -
            1) || i - j == -(n - 1))
                        Console.Write("*");
                    else
                        Console.Write(" ");
                }
                Console.WriteLine("\n");
            }
            Console.Read();
        }
    }

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