用户处于非活动状态的C#Windows应用程序时未登录 [英] user is not login when he is inactive c# windows application

问题描述

我通过以下方式创建登录表单:我有一个活动/非活动组合框，管理员可以从中选择活动和非活动值以及活动和非活动用户.
我如何在登录时进行检查.我用用户名和密码进行检查.我如何使用用户名和密码进行检查.如何使用用户名和密码进行检查.

i am create login form in that i have active/inactive combobox from where admin select active and inactive value and active and inactive user.
how can i check this at the time of login.i check with username and password how i check with if user is active or not.how can i check with username and password.

const string query1 = ("Select * from emp_tracker_username where username=@username and password=@password");
//cn.Open();
OleDbCommand cmd1 = new OleDbCommand(query1, cn1);
cmd1.Parameters.AddWithValue("@username", txtusername.Text);
cmd1.Parameters.AddWithValue("@password", txtpassword.Text);
OleDbDataAdapter ad1 = new OleDbDataAdapter(cmd1);
DataSet dt1 = new DataSet();
ad1.Fill(dt1);
if (dt1.Tables[0].Rows.Count > 0)
{
    Form f4 = new frmCorporateNewid();
    f4.Show();
    // hiding the first form.
    this.Hide();
}
else
{
    MessageBox.Show("Login Unsucessful...!");
}

推荐答案

您需要修改命令.试试这个:

You need to modify your command. Try this:

const string query1 = ("Select * from emp_tracker_username where username=@username and password=@password");
//cn.Open();
OleDbCommand cmd1 = new OleDbCommand(query1, cn1);
cmd1.Parameters.AddWithValue("@username", txtusername.Text);
cmd1.Parameters.AddWithValue("@password", txtpassword.Text);
OleDbDataAdapter ad1 = new OleDbDataAdapter(cmd1);
DataSet dt1 = new DataSet();
ad1.Fill(dt1);
if (dt1.Tables[0].Rows.Count > 0)
{
    //Active is the table column which is there in datatable of type BIT/Boolean fetched from database
    if(Convert.ToBoolean(dt1.Tables[0].Rows[0]["Active"])){
        //If use is active
        Form f4 = new frmCorporateNewid();
        f4.Show();
        // hiding the first form.
        this.Hide();
    }
    else{
        //Show the message if user is inactive.
        MessageBox.Show("User is inactive. Contact your admin");
    }
}
else
{
    MessageBox.Show("Login Unsucessful...!");
}

--Amit

--Amit

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