单击按钮时在弹出窗口中显示图像 [英] Show image in popup on button click

问题描述

您好，先生，
我想在单击按钮时在弹出窗口中显示图像，并且我的按钮在gridview内.
我在会话中有图像路径和名称，该图像路径和名称保存在文件夹中.
例如. -〜/Image/abc.jpg"

谢谢

Hello Sir,
I want to show image in a popup on button click and my button is inside the gridview.
I have image path and name in session which is save in folder.
For eg. - "~/Image/abc.jpg"

Thanks

推荐答案

您可以使用 Asp.Net Ajax ModalPopup [ ^ ]
请参考以下链接:
如何在Gridview中打开模式弹出窗口 [ ^ ]
GridView示例中的 ModalPopupExtender [ ^ ]


希望对您有所帮助.
--Amit

You can use Asp.Net Ajax ModalPopup[^]
Refer the links below:
How To Open Modal PopUp Inside Gridview[^]
ModalPopupExtender in a GridView sample [^]


Hope it helps.
--Amit

尝试一下:

.aspx文件:

try this:

.aspx file:

<cc1:modalpopupextender id="mp1" runat="server" popupcontrolid="Panel1" targetcontrolid="btnShow" xmlns:cc1="#unknown">
    CancelControlID="btnClose" BackgroundCssClass="modalBackground">
</cc1:modalpopupextender>
<asp:panel id="Panel1" runat="server" cssclass="modalPopup" align="center" style="display:none" xmlns:asp="#unknown">
    This is an ASP.Net AJAX ModalPopupExtender Example<br />
<asp:image id="img1" runat="server">
                            ImageUrl='~/Image/abc.jpg'></asp:image>
    <asp:button id="btnClose" runat="server" text="Close" />
</asp:panel>

.aspx.cs文件:(按钮单击事件)

.aspx.cs file: (Button Click Event)

void Btn_Click(Object sender, EventArgs e)
    {
        mp1.show(); // Model popup id .show function is to open poup on button click event
    }

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