如何获得打开的文件路径 [英] How Can I get Opend File Path

问题描述

大家好，

我想实现打开的文件监视"，因此我需要C ++代码来获取打开的文件路径".我打开文件监视的目的是获取有关由计算机用户打开的文件的信息.我该如何实现呢?请建议我...

Hi All,

I want to implement Opened File Monitoring so I need a C++ Code to Get Opened File Path . My aim of this Opened File Monitoring is to get Information about the files opened by the users of machine. how can i implement this please suggest me...

推荐答案

我不确定如果不编写某种监视系统的过滤器驱动程序，是否有可能做到这一点. 显示了API挂钩 [

I am not sure that such a thing is possible without writing some sort of filter driver that monitors the system. API hooking revealed[^] is an article that shows some of the techniques that may help you.

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