Java中将Bin转换为Dec错误结果? [英] Convert Bin to Dec in Java Wrong result ?

问题描述

public double Bin2Dec(String n)
        {
            double result= 0;
            for (int i = n.length() - 1; i >= 0; i--)
            {
                result += (int)(n.charAt(i)) * luythua(2, n.length() - i-1);
            }
            return result; 
        }

public double luythua(int x, int n)
        {
            if (x == 0)
                return 0;
            if (n == 0)
                return 1;
            return x * luythua(x, n - 1);
        }

使用该代码，当我调用Bin2Dec("111")时返回343.0(不是7)
大家都帮我解决这个难题吗?谢谢！

With that code, When I call Bin2Dec("111") return 343.0 (not 7)
everyone help me resolves this proplem? thanks !

推荐答案

您需要做的就是从零开始.然后针对字符串中的每个字符:
将结果左移1位
屏蔽掉字符的低位并将其添加到结果中
重复

注意:使用整数值时请勿使用double.

All you need to do is start with a result value of zero. Then for each character in the string:
shift the result left 1 bit
mask off the low order bit of the character and add it to the result
repeat

Note: do not use doubles when working with integer values.

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