如何在两个音频文件在机器人彼此的顶部相结合 [英] How to combine two audio files on top of each other in android

问题描述

我有2个音频文件。第一是背景音乐和第二个是一个讲话。 （他们每个人都在约4分钟长度）

I have 2 audio files. the first is background music and the second is a speech. (Each of them is about 4 minutes in length)

现在我想将它们混合并获得4分钟的演讲用的背景音乐。

Now I want to mix them and receive a 4 minute speech with a background music.

推荐答案

您不需要FFmpeg中，可以使用现有的标准codeCS在android系统。

You don't need FFMPEG, you can use the standard codecs available in android.

   public void playFile(String fileToPlay)
    {
     // see where we find a suitable autiotrack
        MediaExtractor extractor = new MediaExtractor();
        try
        {
            extractor.setDataSource(fileToPlay);
        }
        catch (IOException e)
        {
            out.release();
            return;
        }
   extractor.selectTrack(0);

    String fileType=typeForFile(fileToPlay);
    if (fileType==null)
    {
        out.release();
        extractor.release();
        return;
    }

    MediaCodec codec = MediaCodec.createDecoderByType(fileType);
    MediaFormat wantedFormat=extractor.getTrackFormat(0);
    codec.configure(wantedFormat,null,null,0);
    codec.start();

    ByteBuffer[] inputBuffers = codec.getInputBuffers();
    ByteBuffer[] outputBuffers = codec.getOutputBuffers();

    // Allocate our own buffer
    int maximumBufferSizeBytes = 0;
    for(ByteBuffer bb:outputBuffers)
    {
        int c=bb.capacity();
        if (c>maximumBufferSizeBytes) maximumBufferSizeBytes=c;
    }
    setupBufferSizes(maximumBufferSizeBytes/4);

    final MediaCodec.BufferInfo bufferInfo=new MediaCodec.BufferInfo();
    MediaFormat format=null;
    while(true)
    {
        long timeoutUs=1000000;
        int inputBufferIndex = codec.dequeueInputBuffer(timeoutUs);
        if (inputBufferIndex >= 0)
        {
            ByteBuffer targetBuffer = inputBuffers[inputBufferIndex];
            int read = extractor.readSampleData(targetBuffer, 0);
            int flags=extractor.getSampleFlags();
            if (read>0)
                codec.queueInputBuffer(inputBufferIndex, 0,read, 0, flags);
            else
                codec.queueInputBuffer(inputBufferIndex, 0, 0, 0, MediaCodec.BUFFER_FLAG_END_OF_STREAM);
            extractor.advance();
        }

        int outputBufferIndex = codec.dequeueOutputBuffer(bufferInfo,timeoutUs);
        if (outputBufferIndex >= 0)
        {
            final boolean last = bufferInfo.flags == MediaCodec.BUFFER_FLAG_END_OF_STREAM;

            int s=bufferInfo.size/4;
            ByteBuffer bytes=outputBuffers[outputBufferIndex];
            ((ByteBuffer)bytes.position(bufferInfo.offset)).asShortBuffer().get(shorts,0,s*2);
            process(shorts,0,s*2);

            codec.releaseOutputBuffer(outputBufferIndex, false);
            if (last)
                break;
        }
        else if (outputBufferIndex == MediaCodec.INFO_OUTPUT_BUFFERS_CHANGED)
        {
            outputBuffers = codec.getOutputBuffers();
        }
        else if (outputBufferIndex == MediaCodec.INFO_OUTPUT_FORMAT_CHANGED)
        {
            format = codec.getOutputFormat();
        }
    }

    extractor.release();
    codec.stop();
    codec.release();

1文件看完上面的code交易。的进程例程（其尚未定义）接收采样的交错阵列（左/右/左/右/左/右）。所有你现在需要做的就是添加这些渠道的目标缓冲区。例如

The above code deals with the reading of 1 file. The 'process' routine (which isn't defined yet) receives an interleaved array of samples (left/right/left/right/left/right). All you need to do now is add these channels to a target buffer. E.g

short[] target=new short[LENGTH OF 4 MINUTES];
int idx=0;
process(short[] audio, int l)
{
  for(int i=0;i<l;i++)
  target[idx++]+=audio[i]/2;
}

然后将得到的目标阵列包含您的覆盖样本。

The resulting target array contains then your overlaid samples.

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