jQuery滑块问题 [英] Problem with Jquery slider
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问题描述
大家好，
我正在将jQuery滑块与php，mysql
一起使用
它正在获取数据，但显示不正确
请帮助我.
这是我的代码
Hi everyone,
i am using jquery slider with php,mysql
it is fetching the data but not displaying correctly
please help me in this.
Here is my code
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" dir="ltr">
<head profile="http://gmpg.org/xfn/11">
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Featured Content Slider Using jQuery - Web Developer Plus Demos</title>
<link rel="stylesheet" type="text/css" href="style.css" />
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js" ></script>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.5.3/jquery-ui.min.js" ></script>
<script type="text/javascript">
$(document).ready(function(){
$("#featured > ul").tabs({fx:{opacity: "toggle"}}).tabs("rotate", 5000, true);
});
</script>
</head>
<body>
<?php
include("connection.php");
$query=mysql_query("select * from images");
while($row=mysql_fetch_array($query))
{
echo "
<div id='featured' >
<ul class='ui-tabs-nav'>
<li class='ui-tabs-nav-item ui-tabs-selected' id='nav-fragment-1'><a href='#fragment-1'><span>".$row['imageid']." Photographs</span></a></li>
</ul>
<!-- First Content -->
<div id='fragment-1' class='ui-tabs-panel' style=''>
<img src=".$row['imagepath']." alt='' />
<div class='info' >
<h2><a href='#' >15+ Excellent High Speed Photographs</a></h2>
<p>".$row['Description']."<a href='#' >read more</a></p>
</div>
</div>
</div>
</div>
</body>";
}
mysql_close($con);
?>
</html>
推荐答案
(document).ready(function(){
(document).ready(function(){
(#featured> ul"). tabs({fx:{opacity:"toggle"}}).tabs("rotate"，5000，true); }); < /script > < /head > < 正文 > <? php include("connection.php");
("#featured > ul").tabs({fx:{opacity: "toggle"}}).tabs("rotate", 5000, true); }); </script> </head> <body> <?php include("connection.php");
查询 = 选择 * 来自 图像")； while(
query=mysql_query("select * from images"); while(
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