检测DPI，计算监视器的物理尺寸 [英] Detect DPI, calculate physical dimension of monitor
问题描述
大家好，
我想获取显示器的显示尺寸..
可以使用Flash的JavaScript吗?
我尝试了以下功能:
Hi all,
I want to get the Display Dimensions of my Monitor..
Is it possible to do with JavaScript of Flash?
I tried the following function:
var dpi_x = document.getElementById(''testdiv'').offsetWidth;
var dpi_y = document.getElementById(''testdiv'').offsetHeight;
var width_in = screen.width / dpi_x;
var height_in = screen.height / dpi_y;
var diagonal_in = Math.round(10 * Math.sqrt(width_in * width_in + height_in * height_in)) / 10;
但是它不显示固定的对角线值..因为当我更改显示分辨率时..
我希望固定尺寸如16.5....我的意思是应该为任何特定的显示器固定尺寸..
but it doesnt shows the fixed diagonal value..because when i change the resolution of display..
Where as i want the fixed dimension like 16.5"....i mean it should be fixed for any specific monitor..
推荐答案
use below code
screen.width;
screen.height;
尝试查询
此处你去，这会做到的.
我的屏幕是13.5 x 7.5英寸-它是15.3英寸的屏幕.
这(错误)将其计算为14.22 x 8-或16.3"
不知道为什么会给出错误的结果-它给出的dpi为96，听起来不错，并在我的显示设置中签出. (**请参阅下面的编辑以获取更新**)
正如我之前所暗示的，我只是将元素的大小设置为1"x1"，然后得到它的大小(以像素为单位)，并根据像素/英寸和屏幕计算出屏幕的物理尺寸.分辨率.
随着屏幕分辨率的变化，如果屏幕模式在屏幕的侧面具有黑色的竖线，则返回的大小也会改变.也就是说，它可以测量包含内容的屏幕的大小.我将其设置为1024 * 768，并在屏幕的任一侧形成了约150像素的黑条.垂直大小保持不变，但水平&对角线尺寸缩小.
Here you go, this will do it.
My screen is 13.5 x 7.5 inches - it''s a 15.3" screen.
This (wrongly) calculates it as 14.22 x 8 - or 16.3"
Don''t know why it gives the wrong result - it gives the dpi as 96 which sounds right and checks out in my display settings. (** See edit below for update **)
As I hinted earlier, I''ve just set the size of an element to be 1"x1" I then get it''s size in pixels and calculate the screen''s physical size based on the pixels/inch and the screen resolution.
As screen resolution changes, the size returned changes if the screen-mode has black vertical bars on the sides of the screen. That''s to say it measures the size of the screen that contains content. I set 1024*768 and got ~ 150pixels of black bars on either side of the screen. The vertical size stayed the same, but the horizontal & diagonal dimensions shrunk.
<!DOCTYPE html> <html> <style> #myDiv { width: 1in; height: 1in; padding: none; margin: none; background-color: black; } </style> <script> function getSize() { var tgt = document.getElementById('myDiv'); tgtX = tgt.clientWidth;//offsetWidth; tgtY = tgt.clientHeight;//offsetHeight; var width_in = screen.width / tgtX; var height_in = screen.height / tgtY; width_in = parseInt(width_in * 100); width_in /= 100; diag = Math.sqrt( width_in*width_in + height_in*height_in); //alert('Div size: ' + tgtX + "x" + tgtY + " px."); alert('Screen size: ' + width_in + "\" x " + height_in + "\" - Diagonal: " + diag + "\""); } </script> </head> <body onload='getSize();'> <div id='myDiv'></div> <body> </html>
将宽度和高度设置为2.7cm而不是1in表示正方形在我的屏幕上为1英寸.然后，这或多或少地给出了正确的结果. 13.39英寸x 7.52英寸(15.36英寸直径)
Setting the width and height to 2.7cm instead of 1in means the square measures 1inch on my screen. This then gives more or less the right results. 13.39" x 7.52" (15.36" diag)
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