绑定Gridview中的异常 [英] Exception in Binding Gridview

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本文介绍了绑定Gridview中的异常的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

public static void BindGridView(string qr, GridView grd)
   {
       //con = new SqlConnection(connectionstring);
       //openconnection();

       dap = new SqlDataAdapter(qr, con);
       DataSet ds = new DataSet();
       dap.Fill(ds);
       grd.DataSource = ds.Tables[0].DefaultView;
       grd.DataBind();  //it is generating error at this function of binding.

   }

推荐答案


检查此
跟我一起工作
Hi ,
Check this
it''s working with me
protected void Page_Load(object sender, EventArgs e)
   {
       if (!IsPostBack)
       {
           BindGridView("select * from ODetails", GridView1);
           GridView1.DataBind();
       }
   }
   SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["testConnectionString"].ConnectionString);
   SqlDataAdapter dap;
   void BindGridView(string qr, GridView grd)
   {
       //con = new SqlConnection(connectionstring);
       //openconnection();

       dap = new SqlDataAdapter(qr, con);
       DataSet ds = new DataSet();
       dap.Fill(ds);
       grd.DataSource = ds.Tables[0].DefaultView;
       grd.DataBind();  //it is generating error at this function of binding.

   }


最好的问候
M.Mitwalli


Best Regards
M.Mitwalli


Dataset objdatset = new dataset();
sqlconnection objcon = new sqlconnection(" ");
sqldataadapter objdataadpter = new sqldatadapter(" select * from emp",objcon);
objadapter.fill(objdataset,"Emp");
gridview1.datasource=objdataset;
gridivew.databind();


检查是否可以正常工作...谢谢..


check for this should works... thankz..


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