绑定Gridview中的异常 [英] Exception in Binding Gridview
本文介绍了绑定Gridview中的异常的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
public static void BindGridView(string qr, GridView grd)
{
//con = new SqlConnection(connectionstring);
//openconnection();
dap = new SqlDataAdapter(qr, con);
DataSet ds = new DataSet();
dap.Fill(ds);
grd.DataSource = ds.Tables[0].DefaultView;
grd.DataBind(); //it is generating error at this function of binding.
}
推荐答案
检查此
跟我一起工作
Hi ,
Check this
it''s working with me
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack)
{
BindGridView("select * from ODetails", GridView1);
GridView1.DataBind();
}
}
SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["testConnectionString"].ConnectionString);
SqlDataAdapter dap;
void BindGridView(string qr, GridView grd)
{
//con = new SqlConnection(connectionstring);
//openconnection();
dap = new SqlDataAdapter(qr, con);
DataSet ds = new DataSet();
dap.Fill(ds);
grd.DataSource = ds.Tables[0].DefaultView;
grd.DataBind(); //it is generating error at this function of binding.
}
最好的问候
M.Mitwalli
Best Regards
M.Mitwalli
Dataset objdatset = new dataset();
sqlconnection objcon = new sqlconnection(" ");
sqldataadapter objdataadpter = new sqldatadapter(" select * from emp",objcon);
objadapter.fill(objdataset,"Emp");
gridview1.datasource=objdataset;
gridivew.databind();
检查是否可以正常工作...谢谢..
check for this should works... thankz..
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