如何获得文件ID，所以我可以从谷歌云端硬盘API在Android上执行下载的文件 [英] How to get the file ID so I can perform a download of a file from Google Drive API on Android

问题描述

我工作的一个机器人项目，我想利用谷歌云端硬盘API的，我已经得到了大部分工作，但我有在问题要如何进行下载。

I am working on an android project and I am trying to make use of the Google Drive API and I've got most of it working but I am having an issue in how I perform a download.

我找不到任何地方我是怎么得到的文件ID，这样我可以进行下载。为了测试我检索到的所有文件在我的硬盘帐户，并将其添加到列表数组，然后得到了ID在列表中的第一个文件。

I can't find anywhere how I get the file ID so that I can perform the download. In order to test I've retrieved all files in my drive account and added them to a list array and then got the ID for the first file in the list.

我再复制文件ID到命令下载文件，而这成功的工作，但我不知道如何让特定的文件我想下载的文件ID。

I then copied the file ID in to the command to download the file and this worked successfully but I have no idea how to get the file id of the specific file I want to download.

下面是code我使用下载的文件。

Below is the code I am using to download the file.

private void downloadFile()
{
    Thread thread = new Thread(new Runnable() {

        @Override
        public void run() {
            try 
            {
                com.google.api.services.drive.model.File file = service.files().get("0B-Iak7O9SfIpYk9zTjZvY2xreVU").execute();
                //FileList file = service.files().list().execute();
                //List<com.google.api.services.drive.model.File> fileList = file.getItems();
                //com.google.api.services.drive.model.File fileItem = fileList.get(0);
                //Log.d("FileID" , fileItem.getId());
                //Log.d("Count", "Retreived file list");
                if (file.getDownloadUrl() != null && file.getDownloadUrl().length() > 0)
                {
                    HttpResponse resp = service.getRequestFactory().buildGetRequest(new GenericUrl(file.getDownloadUrl())).execute();
                    InputStream inputStream = resp.getContent();
                    writeToFile(inputStream);
                }
            } 
            catch (IOException e)
            {
                Log.e("WriteToFile", e.toString());
                e.printStackTrace();
            }
        }
    });
    thread.start();
}

0B-Iak7O9SfIpYk9zTjZvY2xreVU 是我下载的文件时，我做了一个列表，选择第一个文件，我检索到的文件ID，但我怎么能说我想下载，File_1并获得其ID来那么这传递给service.get（）函数执行。

0B-Iak7O9SfIpYk9zTjZvY2xreVU is the file ID of the file that I download which I retrieved when I did a list and selected the first file, but how can I say I want to download, File_1 and get its ID to then pass this to the service.get().execute function.

基本上我的最终目标是我的应用程序中，我上传一个XML文件来谷歌驱动器，然后后来就下载文件。这将只有一个文件，将始终具有相同的名称。我要去一下吧马上或是否有更好的方法来实现我想做的事情。

Basically my end goal is within my app, I upload an XML file to Google Drive, and then later on Download the file. It will only be one file and will always have the same name. Am I going about it the right away or is there a better way to achieve what I am trying to do.

我希望这是有道理的，任何帮助将大大AP preciated。

I hope this makes sense, any help would be greatly appreciated.

感谢

推荐答案

嗯，我能想到的第一个选项是，你可以使用的列表要求=htt​​ps://developers.google.com/drive/search-parameters相对=nofollow>搜索参数的为您的文件，如标题=File_1.xml和fileExtension =XML。它要么返回文件的空列表（没有一个匹配检索算法的标准），或具有至少一个文件返回的列表。如果是只有一个 - 它很容易。但是，如果有更多的 - 你必须选择基于一些其他领域的其中之一。请记住，在你的GDrive可能有超过1个文件具有相同的名称。所以你提供更多的搜索参数，就更好了。

Well the first option I could think of is that you could send a list request with search parameters for your file, like title="File_1.xml" and fileExtension="xml". It will either return an empty list of files (there isn't one matching the serach criteria), or return a list with at least one file. If it's only one - it's easy. But if there are more - you'll have to select one of them based on some other fields. Remember that in gdrive you could have more than 1 file with the same name. So the more search parameters you provide, the better.

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