如何在包含一个变量的类中使用多个属性? [英] How to use multi properties in class that contain one variable?

问题描述

你好.
如果您能帮助我，将不胜感激.我有一个名为config的类，该类具有名为param的私有字符串变量.

我需要从config类的param变量中获取，有时以int类型获取，有时以bool类型或字符串获取.
据我了解，我需要在config类中创建3个属性，每个属性都必须转换类型，如下所示:

第一个属性将字符串转换为int，第二个属性将字符串转换为bool，第三个属性为我获取字符串值.

该类应该看起来像这样.

Hello.
Would be very grateful if you help me. I have class named config that have private string variable named param.

I need to get from config class param variable sometimes as int type sometimes as bool type or string.

As I understand I need create 3 properties in config class,each property have to convert type, as follow:

the first property converts string to int, the second converts string to bool, the third property gets me the string value.

The class should look something like this.

class Config
{
    private string param; 

    public int
    {
       get 
      { 
        return int.parse(param); 
      }
    }

    public bool
    {
       get 
      { 
        return bool.tryparse(param); 
      }
    }

   public string
    {
       get 
      { 
         return param; 
      }
    }
}

但是我不知道如何根据我要离开课堂的变量类型使用这些属性.

我希望你能帮帮我！！

But I dont know how can those properties be used in accordance to the variable type that I want to get out of class.

I hope you can help me!! Thank you in advance!

推荐答案

即使请求有点奇怪，也应该是解决方案(即使从概念上讲是错误的):

Even if the request is a kind of strange, this should be the solution (even if it is conceptually wrong):

public class Config
{
    private string param;

    public bool MyBool
    {
        get { return bool.Parse(param); }
    }

    public int MyInt
    {
        get { return int.Parse(param); }
    }

    public string My
    {
        get { return param; }
    }
}

然后将其简单地用作:

Then use it simply as:

Config c = new Config();

int i = c.MyInt;

干杯

Cheers

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