如何在运行时创建多个文本框以及如何访问它? [英] How to create multiple textbox at runtime and how can access it?

问题描述

我想使用按钮单击事件在运行时创建多个文本框.以及如何获取文本框ID，即如何访问它? 我已实现在运行时创建多个文本框，但无法访问它.
这是在运行时创建多个文本框的代码...

I would like to create multiple textbox at runtime using a button click event. And how can i get the textboxes id i.e. how can i access it????
I have implemented to create a multiple textbox at runtime but i can''t access it.
Here is the code to create multiple textbox at runtime...

namespace multiple_textbox
{
    public partial class Form1 : Form
    {

        int a = 0;

        public Form1()
        {
            InitializeComponent();
        }

        private void btntxtbx_Click(object sender, EventArgs e)
        {
            a++;

            int count = 0 + a ;
            TextBox[] t = new TextBox[count];
            int x = 70, y = 50;
            for (int i = 0; i < count; i++)
            {
                t[i] = new TextBox();
                if(this.Width!=1152)
                {
                t[i].Location = new System.Drawing.Point(y +(i*65), x);
                t[i].Size = new Size(100, 50);
                t[i].Name = "txtbx" + i.ToString();
                this.Controls.Add(t[i]);
                this.ResumeLayout(false);
                y += 40;
                this.Refresh();
                }
            }

        }

    }
}

推荐答案

设置

TextBox[] t

更大的范围.
在课程级别定义它.

bigger scope.
Define it in class level.

int a = 0;
     TextBox[] t;

     public Form1()
     {
         InitializeComponent();
     }

     private void btntxtbx_Click(object sender, EventArgs e)
     {
         a++;

         int count = 0 + a;
         t = new TextBox[count];
         int x = 70, y = 50;
         for (int i = 0; i < count; i++)
         {
             t[i] = new TextBox();
             if (this.Width != 1152)
             {
                 t[i].Location = new System.Drawing.Point(y + (i * 65), x);
                 t[i].Size = new Size(100, 50);
                 t[i].Name = "txtbx" + i.ToString();
                 this.Controls.Add(t[i]);
                 this.ResumeLayout(false);
                 y += 40;
                 this.Refresh();
             }
         }

     }

     private void button2_Click(object sender, EventArgs e)
     {
         if (t == null)
             return;

         TextBox t2 = t.Where(o => o.Name == "txtbx0")
             .FirstOrDefault() as TextBox;

         Console.WriteLine("txtBox: "+t2.Name);

     }

希望对您有帮助.

Hope this will help you.

设置每个texdtbox的ID
喜欢

Set the Id of each texdtbox
Like

t[i].ID = "TestBox" + i.ToString();

在按钮单击事件之外声明该文本框对象.
意思是:全球性
现在尝试使用其ID访问文本框.

一条建议:
您已经写了

declare that textbox object outside the button click event.
Means:Globaly
Now try to access the textbox using their ID.

One suggestion:
You have written that

int count = 0 + a;

我认为不需要写0 +瞬间，只需写

I think no need to write 0 + a instant of that simply write

int count = a;

首先，很可能您以后需要访问文本框.如何?只需使引用TextBox[] t在您需要的生存期内即可访问.通常，您需要使此数组引用表单类的字段或属性. (仅给它一个好的语义名称；使用一个字符的标识符总是很不好的.)

您的代码有许多问题要解决.不好的事情是所有在代码中硬编码的立即常量:70、50、1142、65、100、50，"txtbx"…然后声明所有显式常量或放入资源中.对这些控件的父级使用带有停靠/填充的单独面板.一个明显的问题是尺寸.您永远不要分配高度；它应该保持默认值.一个明显的问题是您不知道索引的大小就按索引排列控件.您应该做一件非常不同的事情；更好地垂直排列它们并计算高度以确定垂直步长:

First of all, most likely you will need to access the text boxes later. How? Simply make the reference TextBox[] t accessible during the life time you need. Most usually, you would need to make this array reference a field or a property of your form class. (Only give it a good semantic name; using one-character identifiers is always bad.)

You code has a number of problems to fix. Bad things is all your immediate constants hard-coded in the code: 70, 50, 1142, 65, 100, 50, "txtbx"… Declare then all explicit constants or put in resources. Use a separate panel with docking/padding for a parent of these controls. One apparent problem is the size. You should never assign the height; it should remain default. One apparent problem that you arrange the controls by index without knowing its size. You should do a very different thing; better arrange them vertically and calculate the height to determine the vertical step:

int gap = 4;
for (int i = 0; i < count; i++) {
    t[i] = new TextBox();
    //if (this.Width != 1152) silly check, if will give you always true or always false
    {
       t[i].Location = new System.Drawing.Point(y * (t[i].Height + gap), x); //height it taken into account
       //...
       this.Controls.Add(t[i]);
    }
}

最后，删除Refresh和ResumeLayout.有时您需要ResumeLayout，但肯定不在循环之内.

—SA

Finally, remove Refresh and ResumeLayout. Sometimes you need ResumeLayout, but certainly out of the loop.

—SA

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