ArrayAdapter的getView（）方法是没有得到所谓的 [英] The getView() method of ArrayAdapter is not getting called
问题描述
我很新的Android开发。我试图构建与（这是通过添加片段）标记的应用程序。在片段中的一个，我想显示一个列表。这份名单已经用ListAdapter我从ArrayAdapter延长填充，我已经超载getView（）方法。
这是我的片段
I am very new to android development. I am trying to a build an application with tags (which are added through fragments). In one of the fragments, I am trying to display a list. This list has been populated using ListAdapter which I have extended from ArrayAdapter and I have overloaded getView() method. This is my fragment
public class tabcontentActivity extends Fragment {
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
if (container == null) {
return null;
}
View v = (LinearLayout) inflater.inflate(R.layout.tablayout, container,
false);
ListView lv = (ListView) v.findViewById(R.id.listview1);
ListViewAdapter adapter = new ListViewAdapter(container.getContext(),
android.R.layout.simple_list_item_1, R.id.textview1);
adapter.notifyDataSetChanged();
lv.setAdapter(adapter);
return v;
}
}
这是多么我已经实现了ListAdapter
And this is how I have implemented the ListAdapter
public class ListViewAdapter extends ArrayAdapter {
Context context1;
public ListViewAdapter(Context context,int resource, int textViewResourceId) {
super(context,resource,textViewResourceId);
this.context1 = context;
System.out.println("here aswell!!!!!!");
// TODO Auto-generated constructor stub
}
public View getView(int arg0, View convertView, ViewGroup arg2) {
// TODO Auto-generated method stub
System.out.println("@@@I AM HERE@@@");
LayoutInflater inflater = LayoutInflater.from(context1);
convertView = inflater.inflate(R.layout.tablayout, null);
TextView wv = (TextView) convertView.findViewById(R.id.textview1);
String summary = "<html><body><h1>This is happening!!!</h1></body></html>";
wv.setText(Html.fromHtml(summary));
convertView.setTag(wv);
return convertView;
}
}
布局XML是
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical" >
<ListView
android:id="@+id/listview1"
android:layout_width="fill_parent"
android:layout_height="fill_parent" >
</ListView>
<TextView
android:id="@+id/textview1"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:text="myreader" />
</LinearLayout>
请帮我找到了一种方法，我可以使这项工作。
Please help me to find a way by which I can make this work.
推荐答案
您刚才忘了提供数据的构造函数，然后让在构造函数中调用正确：
You just forgot to provide the data to the constructor and then make the correct call within the constructor:
public ListViewAdapter(Context context,int resource, int textViewResourceId, List<YourObjectType> items) {
super(context,resource,textViewResourceId, items);
this.context1 = context;
// TODO Auto-generated constructor stub
}
这篇关于ArrayAdapter的getView（）方法是没有得到所谓的的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
