帮助! jQuery可拖动的保存位置问题 [英] help! jquery draggable save position problem

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问题描述

我正在尝试创建2个可拖动的框,但是它无法正常工作,因为它无法从上一次拖动中恢复位置.
这是我的愚蠢代码.

I ''m trying to create 2 draggable boxs but it is not work because it can not restore the position from the last dragging.
Here are my stupid codes.

<!DOCTYPE html>
<html lang="en">
<head>
	<meta charset="utf-8">
	<title>Test Draggable</title>
	<link rel="stylesheet" href="sources/jquery.ui.all.css">
	<script src="sources/jquery-1.7.2.js"></script>
	<script src="sources/jquery.ui.core.js"></script>
	<script src="sources/jquery.ui.widget.js"></script>
	<script src="sources/jquery.ui.mouse.js"></script>
	<script src="sources/jquery.ui.draggable.js"></script>
	<script src="sources/jquery.cookie.js"></script>
	<link rel="stylesheet" href="sources/demos.css">
	<style>
	    #draggable1 {top:70px; left:77px; width: 100px; height: 100px; padding: 0.5em; background-color:#E3E4FA;}
	    #draggable2 {top:170px; left:77px; width: 100px; height: 100px; padding: 0.5em; background-color:#E9CFEC;}
	</style>
	<script>

  $(document).ready(function () {
	    $(function() {
	        var d1 = $.cookie('positionD1');
	        var d2 = $.cookie('positionD2');
	        
	        if (d1 && d2) {
	            //alert(d1[0]);
	            var savedPosition1 = $.cookie('positionD1').split(',');
	            $("#draggable1").css({ top: savedPosition1[0], left: savedPosition1[1] });
	            var savedPosition2 = $.cookie('positionD2').split(',');
	            $("#draggable2").css({ top: savedPosition2[0], left: savedPosition2[1] });
	        }

	        $("#draggable1").draggable({
	            stop: function(event, ui) {

	                var currentPos1 = $("#draggable1").position();
	                $.cookie('positionD1', currentPos1.top + ',' + currentPos1.left);
	                //alert($.cookie('positionD1'));
	               // $("#d1").innertext = $.cookie('positionD1');
	            }
	        });
	        $("#draggable2").draggable({
	            stop: function(event, ui) {

	                var currentPos2 = $("#draggable2").position();
	                $.cookie('positionD2', currentPos2.top + ',' + currentPos2.left);
	                //alert($.cookie('positionD2'));
	               // $("#d2").innertext = $.cookie('positionD2');
	            }
	        });

	        $("draggable1").each(function() {
	            var savedPosition1 = $.cookie('positionD1').split(',');
	            $(this).css({ top: savedPosition1(0), left: savedPosition1(1) });
	        });
	        $("draggable2").each(function() {
	            var savedPosition2 = $.cookie('positionD2').split(',');
	            $(this).css({ top: savedPosition2(0), left: savedPosition2(1) });
	        });

	    });
	  });
	    /*$(function() {
	             $("draggable1").each(function() {
	                var savedPosition1 = $.cookie('positionD1').split(',');
	                $(this).css({ top: savedPosition1(0), left: savedPosition1(1) });
	            });
	            $("draggable2").each(function() {
	                var savedPosition2 = $.cookie('positionD2').split(',');
	                $(this).css({ top: savedPosition2(0), left: savedPosition2(1) });
	            });
    	  
	    });*/


	</script>
</head>
<body>

<div class="demo">

    <div id="draggable1" class="ui-widget-content">
	    <p>100x100</p>
	    <p id="d1"></p>
    </div>
    <div id="draggable2" class="ui-widget-content">
	    <p>100x100</p>
	    <p id="d2"></p>
    </div>
    
</div>

</body>
</html>



谢谢您的帮助.



Thank you for help.

推荐答案

(文档).ready(
(document).ready(function () {


( var d1 =
(function() { var d1 =


.cookie(' positionD1'); var d2 =
.cookie('positionD1'); var d2 =


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