在Asp.net上使用JavaScript [英] Using JavaScript with Asp.net

问题描述

在单击LinkBut​​ton时，我正在使用JavaScript打开一个具有特定URL的新窗口.当我再次单击该链接按钮时，它将再次打开另一个窗口.但是我想再次单击该链接按钮，我想在同一窗口中打开该URL，该窗口在第一次单击该链接按钮时就会弹出.

我的代码在下面

Hi,

On clicking on LinkButton i am opening a new window with particular URL using JavaScript. When i am again clicking on that linkbutton it again opens another window. But i want that again clicking on that linkbutton i want to open that URL in the same window which gets popup on clicking the linkbutton at first time.

My code is given Below

void lnkViewOrderDocuments_Click(object sender, EventArgs e)
{
     StringBuilder sb = new StringBuilder();
     if (null != Request.QueryString[CONST_OrderNo])
     {
         string dmuUrl = OrderHelper.SetDMULinkURLFromConfig(Request.QueryString[CONST_OrderNo].ToString(),
        Request.QueryString[CONST_OrderType].ToString());
        sb.Append(@"<script language='javascript' type='text/javascript'>");
        sb.Append(dmuUrl.Trim());
        sb.Append(@"</script>");
        this.RegisterStartupScript("RegisterSalesTextScript", sb.ToString());
           }
       }

推荐答案

如果您使用的是window.open，则指定窗口名称，如下所示

例如:

if you are using window.open then specify windowname as below

for example :

window.open("htp://www.google.com","mycustomwindow")

尝试此Javascript函数:

Try this Javascript function:

function OpenURL()
        {
            var hdnFlag = document.getElementById(''<%= hdn.ClientID %>'');
            if(hdnFlag.Value > 0)
            {
                window.location = "http://www.google.co.in";
            }
            else
            {
                hdnFlag.Value = 1;                
                window.open("http://www.google.co.in"); 
                self.focus();
            }
        }

这里的"hdn"是页面中的隐藏字段，应该跟踪按钮是否已经被单击.

注意:请记住，在页面刷新时，此标志将被重置.

希望对您有所帮助！

Here "hdn" is a hidden field in the page which should keep track if the button is already clicked or not.

Note: Remember that on page refresh this flag will be reset.

Hope this helps!

如果是window.open，请使用window.showModalDialog

in case of window.open use window.showModalDialog

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