Ajax控制的问题 [英] problem with ajax control
本文介绍了Ajax控制的问题的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我在一页中添加了脚本管理器.我得到了错误-只能将ScriptManager的一个实例添加到页面中.请帮助我吗?
i have added script manager in one page. i got error-Only one instance of a ScriptManager can be added to the page.plz help me?
推荐答案
"ScriptManager"必须放置在表单标签内使用runat = server.
您必须将脚本管理器放在form标签之后!
''ScriptManager'' must be placed inside a form tag with runat=server.
you have to put your script manager just after the form tag!
您好,
仅将一个脚本管理器添加到页面...不超过此数量.
如果您添加母版页,它将应用于所有相关的页面.....所以要小心.
好的,再见.
Hello,
Only One Script Manager will be Added to Page...Not More than that.
If u add in Master Page, It will apply to all related Pages.....So be Careful.
Ok, Bye.
我认为但不确定您是否在form标签后写了脚本管理器标签.不是在身体标记之后.
i think but not sure u write you script manager tag after the form tag. not after body tag.
<body><asp:scriptmanager id="ScriptManager1" runat="server" xmlns:asp="#unknown"></asp:scriptmanager></body>
代替写
in place of write
<body>
<form id="form1" runat="server">
<%-- <div style=" padding:1% 1% 1% 1%; width:98%; background-color:#F5F6F7; border-removeddotted 1px #D8D8D8">
<asp:ScriptManager ID="ScriptManager1" runat="server">
这篇关于Ajax控制的问题的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文