如何将图像保存到mysql数据库，保存后必须在相同的位置显示 [英] how to save images to mysql database and after saving it has to be displayed in the same

问题描述

你好

Iam在视图页面中设计了一个表单，该表单看起来像

Helo

Iam designed an form in view page which looks like

<div id="dialog" title="Upload files">
    @using(Html.BeginForm("Upload","Image", FormMethod.Post, new {id="photouploadform", enctype = "multipart/form-data" }))
    {
        <p><input type="file" id="fileUpload" name="fileUpload" size="23"/> </p><br />
        <p><input type="submit" value="Upload file" /></p>
        <input type="hidden" id="Id" value="1" />
    }
</div>

<script type="text/javascript">
    $(function () {
        $('.photoupload').click(function (event) {
            $('#userid').val(event.target.id);
            $('#dialog').dialog('open');
        });

        $('#photouploadform').submit(function () {
            $.getJSON("/Image/Upload/", {
                userid: $('#Id').val(),
                file1: $('#fileUpload')
            },
            function(success){
            alert(str.st)
            },
            function (data) {
                $('#dialog').append('<p>' + data + '</p>');
            });
            return false;
        });

        $("#dialog").dialog({
            autoOpen: false,
            show: "blind",
            width: 400,
            hide: "fade",
            modal: true,
            resizable: false

        });

    });
</script>

在我的控制器中，我给

In my controller i give like

public ActionResult Upload(int userid,HttpPostedFileBase file1)
       {

           Image g = new Image();
           g.Userid = userid;

           if (file1 != null)
           {
               g.Image1 = file1;
           }

           try
           {
               this.dbContext.Add(g);
               this.dbContext.SaveChanges();
           }
           catch
           {

           }

           var str = new { st = "Successfully Saved" };

           return Json(str, JsonRequestBehavior.AllowGet);
       }

当我单击上载时，它显示服务器错误
参数字典包含方法"System.Web.Mvc.ActionResult Upload(Int32，System.Web.HttpPostedFileBase)"中非空类型"System.Int32"的参数"Id"的空条目``Dataview.Controllers.ImageController''.可选参数必须是引用类型，可为空的类型，或者必须声明为可选参数.
谁能知道，请告诉我解决方案

when i click upload it is showing server error
The parameters dictionary contains a null entry for parameter ''Id'' of non-nullable type ''System.Int32'' for method ''System.Web.Mvc.ActionResult Upload(Int32, System.Web.HttpPostedFileBase)'' in ''Dataview.Controllers.ImageController''. An optional parameter must be a reference type, a nullable type, or be declared as an optional parameter.
Can any one knows please tell me the solution

推荐答案

(function(){

(function () {

('.photoupload').click (函数(事件){

('.photoupload').click(function (event) {

('#userid').val(event.target.id);

('#userid').val(event.target.id);

这篇关于如何将图像保存到mysql数据库，保存后必须在相同的位置显示的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！