选择任何项目后如何将组合框列表设置为打开? [英] How to set combobox list open as it is after selecting any item?

问题描述

如何在选择任何项目后将组合框列表设置为打开?

How to set combobox list open as it is after selecting any item?

推荐答案

可以显示所有以combo box键入的字符开头的项目通过设置ComboBox
的以下属性 DropDownStyle [ AutoCompleteMode [自动完成源 [ ^ ]
如下图所示:

All items which start with the characters typed in the combo box can be shown by setting the following properties of ComboBox
DropDownStyle[^], AutoCompleteMode[^] and AutoCompleteSource[^]
as shown below:

comboBox1.DropDownStyle= ComboBoxStyle.DropDown;
comboBox1.AutoCompleteMode =  AutoCompleteMode.SuggestAppend;
comboBox1.AutoCompleteSource = AutoCompleteSource.ListItems;

将ComboBox.DroppedDown属性设置为true应该可以解决问题.

Settin the ComboBox.DroppedDown property to true should do the trick.

你好，

根据解决方案给出的

comboBox1.DropDownStyle = ComboBoxStyle.DropDown;
comboBox1.AutoCompleteMode = AutoCompleteMode.SuggestAppend;
comboBox1.AutoCompleteSource = AutoCompleteSource.ListItems;



我做到了.但仍然无法正常工作.

对于使用AJAX的Google搜索引擎，必须按原样显示组合框列表.但是，在Windows应用程序中如何显示呢?

Hello,

As per given by solution,

comboBox1.DropDownStyle= ComboBoxStyle.DropDown;
comboBox1.AutoCompleteMode = AutoCompleteMode.SuggestAppend;
comboBox1.AutoCompleteSource = AutoCompleteSource.ListItems;



i done it.But still not working properly.

For google search engine by using AJAX have to show combobox list open as it is.But, in windows application how to so it?

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