如何将两个LIst结合到字典 [英] How union two LIst to Dictionary

问题描述

我有两个列表Lst1< string>和Lst2< string>

I have two lists Lst1<string> and Lst2<string>

Lst1                                         Lst2

auto - 1q                                    n122
auto - 2q                                    n341
auto - 3q                                    n461

bus- 1q                                      n132
bus- 2q                                      n441
bus- 3q                                      n761

我想成为:

I want that''s become :

auto
    n122
    n341
    n461

bus
    n132
    n441
    n761

如何使用

How make it with

Dictionary<string, List<string>> axxx = new Dictionary<string, List<string>>();

推荐答案

SAKryukov 对问题的评论是正确的.
要组合两个Lists，基本上需要一个关系才能知道List2 的哪个item 与List1的哪个item 相关.在问题中给出了auto - 1q, auto - 2q, auto - 3q.假设1q, 2q, 3q分别引用List2的第一，第二，第三项，则可以将它们相应地关联起来.但是，对于List1中的bus 项，也给出了1q, 2q, 3q.然后，List2的相同项目再次与此相关.因此，我认为可以通过将List2 中相应项目的正确index赋予List1 中项目的方式来关联，如下所示:

The comment by SAKryukov to the question is correct.
To combine two Lists, basically a relationship is required to know which item of List2 is to be related to which item of List1. In the question auto - 1q, auto - 2q, auto - 3q are given. Assuming that 1q, 2q, 3q refer to the first, second, third items of List2 respectively, they can be related accordingly. But then 1q, 2q, 3q are also given for bus items in List1. Then again the same items of List2 are related to these. Hence, I think it can be related by giving proper index of the corresponding item in List2 to the item in List1 as shown below:

void Main()
{
    List<string> list1 = new List<string>(){"auto - 1","auto - 2","auto - 3","bus - 4","bus - 5","bus - 6"};
    List<string> list2 = new List<string>(){"n122","n341","n461","n132","n441","n761"};
    Dictionary<string, List<string>> refDic = new Dictionary<string, List<string>>();
    foreach(string item in list1){
        string[] keyInd=item.Split(new char[]{'-'});
        int ind = int.Parse(keyInd[1].Trim())-1;
        string refValue = ind < list2.Count ?
                list2[ind] : string.Empty;
        List<string> refValues;
        if (!refDic.TryGetValue(keyInd[0].Trim(),out refValues)){
            refValues = new List<string>();
            refDic.Add(keyInd[0].Trim(),refValues);}
        refValues.Add(refValue);
    }
}
//The contents of refDic will look like
//Key - auto
//Value - List<string> of
//n122
//n341
//n461
//
//Key - bus
//Value - List<string> of
//n132
//n441
//n761

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