计算查询结果中的重复项 [英] counting the duplicates in query result
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问题描述
select A.*,B.sitename,B.buildingno from gen_complaints as A, building_master as B where A.lacation=B.buildingno group by B.buildingno
这是我的查询,它显示出来像滚滚一样
this is my query it is show ing out put like billow
7 GENCN7 2012-04-13 General Low Plumbing 1341 dfgdfshgdsfhgdsfg jana reddy jana@mindworks.co.in 571658 Pending 208 WATTAYAH MOTORS LLC \N \N \N \N \N FARAH BLDG MBD 1341
8 GENCN8 2012-04-13 General High Electrical 1341 hfjgfhjgfj 0 jana@mindworks.co.in 571658 Pending 208 WATTAYAH MOTORS LLC \N \N \N \N \N FARAH BLDG MBD 1341
3 GENCN3 2012-04-05 General Low Plumbing 3425 nmgbv dvbdfbdgfdsgdg 2012-04-25 support client jana@mindworks.co.in 24446501 Mr Waljeet, Badar Completed 17 VOLTAMP TRANSFORMERS OMAN-17 hgj ghj 55.235 gjh 2012-04-11 777 AL KHUWAIR 3425
5 GENCN5 2012-04-10 General Low Landscaping 3425 hfgf 2012-04-30 support g f 456 Completed 0 1 1 1 265.235 1 \N 777 AL KHUWAIR 3425
2 GENCN2 2012-04-05 General High Carpentry 945 ytr 2012-04-17 support jana reddy jana@mindworks.co.in 24703222 /99607687 Completed 17 BAIT AL OSOOL ghj hgj 30.12 ghjghjghjgfjghjghfjhgj 2012-04-12 MQE GARDEN COURT ROOLEH6 945
4 GENCN4 2012-04-06 General Low Carpentry 945 hjkhjkhgfj 2012-04-18 support jana reddy jana@mindworks.co.in 24763542/99796405 Processing 15 BAIT AL OSOOL dgfh fdgh 256.236 rtyytrerghdgfhgfhdgfh 2012-04-13 MQE GARDEN COURT ROOLEH6 945
1 GENCN1 2012-04-05 Equipment High Carpentry 716-SHOP testing 2012-04-30 support jana reddy jana@mindworks.co.in 24784602/99009473 Mr Hanif Pending SAWMDBOO03 6 ABU DOHA TRADING 5 5 25.15 5 \N REX-SHOPS 716-SHOP
9 GENCN9 2012-04-14 General High Carpentry 17 hgjkhgk jana reddy 24714636/24714707 Pending 1 CORNICHE HOTELS CO. L.L.C \N \N \N \N \N CORNICHE HOTEL 17
6 GENCN6 2012-04-12 General Low Plumbing 752 complaint from mindworks office jana reddy jana@aol.com 24814200 Pending 12 MEHDI STORE LLC-752-2 \N \N \N \N \N SEEB SOUQ 752
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如果看到最后一列建筑物编号,则建筑物编号正在重复....
我想算一算,每座建筑物没有重复多少次..
例如,如果1341重复了2次,所以我想算2我该怎么做,
[edit]已添加代码块-OriginalGriff [/edit]
if you see the last column building no, building no is repeating....
i want to count that each building no that how many times it is repeating ..
eg if 1341 repeted 2 times so i want count 2 how can i do this,,
[edit]Code block added - OriginalGriff[/edit]
推荐答案
try:
try :
select B.buildingno, count(*) from from gen_complaints as A, building_master as B where A.lacation=B.buildingno group by B.buildingno
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