c#再次出现问题！ [英] Again Problem with c# !

问题描述

朋友，在我对文件中的所有数据进行排序之后，我有了这种排序方式:
e.x

克里斯蒂亚诺·罗纳尔多
克里斯蒂亚诺·罗纳尔多
克里斯蒂亚诺·罗纳尔多
范佩西
卡里姆·本泽马
莱昂内尔·梅西
莱昂内尔·梅西
...
...

现在，我需要像这样的代码:

克里斯蒂亚诺·罗纳尔多[3]
范佩西[1]
卡里姆·本泽马[1]
利昂·梅西[2]


因此，用相同的名称和Surnme重复多少次才能在方括号中告诉[] ...

Hi friends, After I sort all the data from a file, I have this kind of sort :
e.x

Cristiano Ronaldo
Cristiano Ronaldo
Cristiano Ronaldo
Van Persi
Karim Benzema
Lionel Messi
Lionel Messi
...
...

Now I need the code that this sort make like that :

Cristiano Ronaldo [3]
Van Persi [1]
Karim Benzema [1]
Lione Messi [2]


So, how many time is repeat the same name and surnme to tell in brackets []...

推荐答案

Hello

例如，您有一个名称的数据集.假设它是一个列表(简单):

Hello

For example you have a DataSet of names. Let''s suppose it''s a List (Simple):

List<string> nameList = new List<string>();
nameList.Add("Cristiano Ronaldo");
nameList.Add("Cristiano Ronaldo");
nameList.Add("Cristiano Ronaldo");
nameList.Add("Van Persi");
nameList.Add("Karim Benzema");
nameList.Add("Lione Messi");
nameList.Add("Lione Messi");
nameList.Add("Ali Karimi");
nameList.Add("Ali Karimi");
nameList.Add("Ali Karimi");
nameList = nameList.OrderBy(n => n).ToList();

所以:

So:

Dictionary<string,> nameDictionary = new Dictionary<string,>();

foreach (string s in nameList)
{
    if (nameDictionary.Keys.Contains(s))
    {
        nameDictionary[s]++;
        continue;
    }
    nameDictionary.Add(s, 1);
}

MyListBox.DataSource = new BindingSource(nameDictionary, null);

并且在表单的构造器中(例如MyForm(){...}):

And In the Consructor of Form (For example MyForm(){...}):

MyListBox.Format += new ListControlConvertEventHandler((object sender, ListControlConvertEventArgs e) =>
{
    KeyValuePair<string, int> item = (KeyValuePair<string, int>)e.ListItem;
    e.Value = string.Format("{0} [{1}]", item.Key, item.Value);
});

以下代码可用于创建名称的唯一列表以及初始列表中出现的次数.

The following code can be used to make distinct list of names along with number of occurances in the initial list.

void Main()
{
    Form form1 = new Form();
    ListBox listBox1 = new ListBox();
    form1.Controls.Add(listBox1);

    List<string> names = new List<string>(){
        "Cristiano Ronaldo",  "Lione Messi",
        "Van Persi", "Karim Benzema", "Lione Messi",
        "Cristiano Ronaldo", "Cristiano Ronaldo"};
    //Make a list of sorted Distinct Names
    var distinctNames = names.Distinct().OrderBy (n => n);
    //Make list of distinctNames with count
    List<string> distinctNamesWithCount = (from name in distinctNames
        select string.Format("{0} [{1}]",name,names.Count (n => n==name ))).ToList();
    listBox1.DataSource=distinctNamesWithCount;
    form1.ShowDialog();
}
//distinctNamesWithCount contents will be

//Cristiano Ronaldo [3]
//Karim Benzema [1]
//Lione Messi [2]
//Van Persi [1]

上面的代码可以使用LINQPad进行快速测试，可以从此处下载 http://www.linqpad.net/ [ ^ ]

The above code can be tested quickly using LINQPad which can be downloaded from here http://www.linqpad.net/[^]

解决方案3不错:)

您也可以尝试这个，

Solution 3 is good :)

You might try this one as well,

using System;
using System.Collections.Generic;
using System.Linq;

namespace Chapter_5
{
    class Program
    {
        static void Main(string[] args)
        {

            List<string> names = new List<string>()
            {
                "Cristiano Ronaldo",  "Lione Messi",
                "Van Persi", "Karim Benzema", "Lione Messi",
                "Cristiano Ronaldo", "Cristiano Ronaldo",
            };
            names.GroupBy(name => name).Select(group => string.Format("{0} [{1}]", group.Key, group.Count()))
                .ToList().ForEach(item => Console.WriteLine(item));
        }
    }
}</string></string>

希望对您有所帮助:)

Hope it helps :)

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