将int转换为字符串并显示 [英] Converting of int to string and displaying

问题描述

使用_ttoi函数将字符串变量转换为int之后，我需要将其转换为String才能显示该值.这是代码:

After converting a string variable into int using _ttoi function , I need to convert it to String to display the value. This is the code :

My function:  

int i;
char buffer[20];
CString str;

i= _ttoi(myVal->GetText());  //convert string to int 
itoa (i,buffer, 10); //convert int back to string 

str.AppendFormat(_T("Value is : %s\n"), buffer);

但这根本不显示任何内容！！！有任何想法吗?

But this does not display anything at all!!! Any ideas?

推荐答案

您根本不需要使用atoi. CString :: AppendFormat或CString :: Format确实可以完成您想做的事情:

You don''t need to use atoi at all. CString::AppendFormat or CString::Format does exactly what you want to do:

int i = 4711;
CString str;
str.Format (_T("My variable has value: %d\n"), i);

CString的格式化能力是最好的，而且非常灵活.

CString''s formatting capacity is one of the best and very flexible.

这是一个技巧吗?您正在混合字符和宽字符.一方面，您使用_ttoi和_T()，然后使用char和itoa.而且您可能使用UNICODE字符集进行构建.

像这样使它起作用.

If this a trick question? You''re mixing chars and wide chars. On one hand you use _ttoi and _T() and then char and itoa. And you probably build with UNICODE char set.

Make it like this and it will work.

int i;
TCHAR buffer[20];
CString str;

i= _ttoi(myVal->GetText());  //convert string to int
_itot(i, buffer, 10); //convert int back to string

str.AppendFormat(_T("Value is : %s\n"), buffer);

但是，为什么要完全使用itoa?只需使用已经指出的CString :: AppendFormat()或CString :: Format().

But why do you use itoa at all? Simply use CString::AppendFormat() or CString::Format() as already pointed out.

您如何显示" str?

how are you "displaying" str ?

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