CLI包装器-奇怪的问题 [英] CLI wrapper - weird problem

问题描述

让我们说我有一个用c ++编写的类

let''s say I have a class written in c++

class Foo
{
 ...
 
 const Foo operator / (Foo& other_Foo)
{
  //internal calculus for division
  //returns new foo
}

 ...
}

现在我写了一个cli包装器

and now I wrote a cli wrapper

public ref class ManagedFoo
{
 ...

 ManagedFoo divide(ManagedFoo& other_ManagedFoo)
{
 //how do I call here the divide from the unmanaged???
}

 ...
}

推荐答案

好吧，我找到了一个解决方案...相当简单...某种复制构造函数.

Well I found a solution...rather straightforward...some sort of copy constructor.

ManagedFoo(ManagedFoo% other_ManagedFoo):Foo_point(other_ManagedFoo.get_native()){}

那就是因为如果我有2个托管foo实例，我想通过调用以下方法获得第三个实例:

thats because If I have 2 managed foo instances I want to get the third by calling:

ManagedFoo one( /*...*/ );
ManagedFoo two( /*...*/ );
ManagedFoo three = one.divide(two);

这是除法实现的代码:

this is the code for the divide implementation:

ManagedFoo ManagedFoo::divide(ManagedFoo %other_ManagedFoo)
{
	Foo res = Foo_point->operator/ (*(other_ManagedFoo.get_native())); 
	ManagedFoo result(new Foo(res));
	return result;
}

您可以说.get_native()返回本机实例的指针.

You can tell that .get_native() returns the pointer of the native instance.

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