打印指针的地址 [英] Print the address of pointer

问题描述

你好，

我想打印指针的地址，以查看程序运行(exe寿命)期间是否发生了变化.

我写道:

Hello,

I would like to print address of pointer in order to see if is changing during program run ( exe life ).

I wrote:

char	DebugString[100];
uint8	*m_pPointer;
void *val1 = pPointer;
sprintf_s(DebugString,"pPointer: %d\n",val1);
OutputDebugString(DebugString);

是打印指针地址的正确方法吗?
指针地址在整个exe生命中都应该是永久的吗?

谢谢，

Tal.

Is it the right way to print address of a pointer?
Should the pointer address be permanent during all exe life?

Thanks,

Tal.

推荐答案

我认为您需要一个指向指针的指针.阅读此内容:

指向指针的指针

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问候

H.Maadani

I think you need a pointer to pointer. read this :

Pointer to pointer

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Regards

H.Maadani

如果要打印pPointer变量的地址，则可以使用&运算符来获取地址的地址 pPointer，如下所示:

If you want print the address of the pPointer variable, you can use the & operator to obtain the address of pPointer, like the following:

void *val1 = &pPointer;

使用应使用 p指定符 [

Use should use the p specifier[^].

sprintf_s(DebugString,"pPointer: %p\n",val1);

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