如何显示先前的实例，如果应用程序已在运行. [英] How to show the previous instance, If application is already run.

问题描述

当用户最小化程序时，我使用NotifyIcon控件隐藏表单并在托盘中显示图标.
如果用户双击图标，则在屏幕上显示该程序.它按顺序工作.

 私有 子 NotifyIcon1_MouseDoubleClick( ByVal 发​​件人 As 系统.对象， ByVal  e  As  System.Windows.Forms.MouseEventArgs)句柄 NotifyIcon1.MouseDoubleClick
        NotifyIcon1.Visible = 错误
        我 .Show()
        我 .WindowState = FormWindowState.Normal
    结束 子

    私有 子 frmGenerateProformaWeeklyLifting_Resize( ByVal 发​​件人 As 系统.对象， ByVal  e  As  System.EventArgs)句柄  MyBase .
        如果 我 .WindowState = FormWindowState.最小化然后
            我 .Hide()
            NotifyIcon1.Visible = 真
        结束 如果
    结束 子 

我的问题是程序已经运行并且在托盘中(图标正在显示，程序处于隐藏状态)，如果用户再次运行该程序(意味着用户再次运行exe)
那么我想显示以前的实例，而不是允许程序运行多个实例.

通过调用以下代码，我可以知道程序是否已经运行，但是我不知道如何显示前一个实例.

 私有  Sub  CheckInstanceOfApp()
     Dim  appProc() As 流程


     Dim  strModName，strProcName  As  字符串
    strModName = Process.GetCurrentProcess.MainModule.ModuleName
    strProcName = System.IO.Path.GetFileNameWithoutExtension(strModName)

    appProc = Process.GetProcessesByName(strProcName)
    如果 appProc.Length>  1  然后
        MessageBox.Show(" )

    其他
        MessageBox.Show(" )
    结束 如果

结束 子

非常感谢您的帮助.

谢谢和最好的问候

解决方案

通过使用命名的Mutex，您可以做到这一点.首先创建一个名为Mutex的文件，并在启动应用程序时进行检查.这是一个可以帮助您单实例C#应用程序-.NET 2.0的链接 [ ^ ]

I找到了解决方法

这些是我的做法
1.制作单个实例
在应用程序"选项卡上转到项目属性"，然后选中制作单实例应用程序".
2.显示以前的实例
在"Application.Designer.vb"中选择"StartupNextInstance"事件，添加"e.BringToForeground = True"

例如.

 私有  Sub  MyApplication_StartupNextInstance( As   ByVal  e  As  Microsoft.VisualBasic.ApplicationServices.StartupNextInstanceEventArgs)句柄 真
           frmGenerateProformaWeeklyLifting.NotifyIcon1.Visible = 错误
           我 .MainForm.Show()
           我 .MainForm.WindowState = FormWindowState.Normal
       结束 子

它确实适合我的情况.


Laxmikant_Yadav，谢谢您的回答.您能帮我吗，我在VB中使用Visual Studio 2010 Ultimate.我只是不太明白这是子还是什么.

I use NotifyIcon control to hide the form and show icon in tray when user minimize the program.
If user Double click on icon then show the program on screen. It works in order.

Private Sub NotifyIcon1_MouseDoubleClick(ByVal sender As System.Object, ByVal e As System.Windows.Forms.MouseEventArgs) Handles NotifyIcon1.MouseDoubleClick
        NotifyIcon1.Visible = False
        Me.Show()
        Me.WindowState = FormWindowState.Normal
    End Sub

    Private Sub frmGenerateProformaWeeklyLifting_Resize(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Resize
        If Me.WindowState = FormWindowState.Minimized Then
            Me.Hide()
            NotifyIcon1.Visible = True
        End If
    End Sub

My problem is while the program is already run and it''s in tray(icon is showing and program is hiding status), if user run the program again(means user run exe again)
then I want to show previous instance instead of allow program running multiple instance.

By calling the following code I can know if program is already run, but I don''t know how to show the previous instance.

Private Sub CheckInstanceOfApp()
    Dim appProc() As Process


    Dim strModName, strProcName As String
    strModName = Process.GetCurrentProcess.MainModule.ModuleName
    strProcName = System.IO.Path.GetFileNameWithoutExtension(strModName)

    appProc = Process.GetProcessesByName(strProcName)
    If appProc.Length > 1 Then
        MessageBox.Show("There is an instance of this application running.")

    Else
        MessageBox.Show("There are no other instances running.")
    End If

End Sub

Would appreciate your help.

Thanks and Best Regards

解决方案

By Using Named Mutex you can do this. First create a named Mutex and check for it while starting your application. Here is one link which might help you Single-Instance C# Application - for .NET 2.0[^]

I found the solution

These are how I did
1. To make single instance
Got to Project Properties at "Application" Tab, then checked "Make Single instance application".
2. To show previous instance
In "Application.Designer.vb" Select "StartupNextInstance" event add "e.BringToForeground = True"

eg.

Private Sub MyApplication_StartupNextInstance(ByVal sender As Object, ByVal e As Microsoft.VisualBasic.ApplicationServices.StartupNextInstanceEventArgs) Handles Me.StartupNextInstance
           e.BringToForeground = True
           frmGenerateProformaWeeklyLifting.NotifyIcon1.Visible = False
           Me.MainForm.Show()
           Me.MainForm.WindowState = FormWindowState.Normal
       End Sub

It did work for my case.


Laxmikant_Yadav, thank you for your answer.

Hello, I had that same problem, still cant figure out what im doing wrong. Can you please help me, I am using visual studio 2010 ultimate in VB. I just don''t quite understand if this is a sub or what.

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