AWK内置变量转换为bash变量 [英] AWK builtin variable to bash variable

问题描述

我想将内置变量FNR分配给bash脚本变量，就像这样，"$ TOT_RECORDS = FNR"



awk'{print NR-1"\ t" $ 0; }''$ INPUT_FILE> $ OUTPUT_FILE

如果我这样做，我将获得每个迭代编号，而我只想要总数；

TOT_RECS = $(awk``{print NR-1;}''$ INPUT_FILE)

还是这个，我确实得到了总数，但是如何将其分配给全局变量?;

awk''END {print NR}''$ INPUT_FILE



通过awk，我想读取输入文件，然后输出到带有前缀行号的新文件，并将总行号返回到全局脚本var中.我在这里还想念什么
wc -l可以毫无麻烦地工作. ;-)

i''m wanting to assign the builtin variable FNR to a bash script variable, something like this, ''$TOT_RECORDS = FNR''



awk ''{ print NR-1 "\t" $0; }'' $INPUT_FILE >$OUTPUT_FILE

and if i do this, i get each iteration number & i only want the total;

TOT_RECS=$(awk ''{ print NR-1; }'' $INPUT_FILE)

or this and i do get the total number, but how to assign it to global var?;

awk ''END {print NR}'' $INPUT_FILE



via awk, i would like to read the input file, then output to new file with prefix line numbers and return total line numbers into a global script var. what am i missing here besides,
`wc -l` would work without all this hassle. ;-)

推荐答案

TOT_RECORDS = FNR''



awk''{print NR-1"\ t"

TOT_RECORDS = FNR''



awk ''{ print NR-1 "\t"

0; }''

INPUT_FILE>

INPUT_FILE >

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