检索表中的第6至9条记录 [英] Retrieve 6th to 9th record in a table

问题描述

我有一个只有1列的表

名称
A
B
C
D
E
F
G
H
我
J

我想将第6到第9条记录输出为-F G H I

i have a table with only 1 column as

Name
A
B
C
D
E
F
G
H
I
J

i want output as 6th to 9th record as- F G H I

推荐答案

尝试以下方法:

Try this:

SELECT * FROM (SELECT ROW_NUMBER() OVER (ORDER BY column_name) AS RowNum, * FROM Table_name) sub WHERE RowNum between 6 and 9

您必须为此编写程序

You have to write procedure for this

CREATE PROCEDURE ReturnRowsAt
(
  @Startpos int,@Endpos int
)
AS 
Begin
 DECLARE @Table1 AS TABLE (rwid bigint identity(1,1), val nvarchar(255))

INSERT INTO   @Table1 (val)
 SELECT * FROM  yourtablename

SELECT * FROM    @Table1 WHERE rwid between @Startpos and @endpos
End

希望这会有所帮助，然后接受并投票回答
--Rahul D.

Hope this helps if yes then accept and vote the answer
--Rahul D.

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