如何存储midi :: CShortMsg的消息? [英] How to Store the message of midi::CShortMsg?

问题描述

void CDemoDlg::OnNoteOn(CPianoCtrl &PianoCtrl, unsigned char NoteId)
{
    midi::CShortMsg ShortMsg(midi::NOTE_ON, 0, NoteId, 127, 0);
    ShortMsg.SendMsg(m_OutDevice);/* How to store this ShortMsg in another variable what should be the type of variable*/

   

}

namespace midi{
.........
class CShortMsg : public CMIDIMsg
{......
 void SendMsg(midi::CMIDIOutDevice &OutDevice);
.......
}

如何将这个ShortMsg存储在另一个变量中，变量的类型应该是什么?

How to store this ShortMsg in another variable what should be the type of variable?
Is it possible to store the message that we are sending to m_OutDevice?

推荐答案

您已经将其包含在变量中:ShortMsg，它是该类的变量，是否可以存储我们要发送到m_OutDevice的消息? midi::CShortMsg.也许您可以尝试改写您的问题.

You already have it in a variable: ShortMsg, which is a variable of the class midi::CShortMsg. Perhaps you could try rephrasing your question.

midi :: CShortMsg没有默认的构造函数.因此，在您的结构中，您将需要对其进行初始化.

midi::CShortMsg doesn''t have a default constructor. So in your struct you''ll need to initialize it.

struct Records 
{ 
    midi::CShortMsg Message;

public:
   Records(void);
   Records(unsigned char Command, unsigned char Channel,
            unsigned char Data1, unsigned char Data2, DWORD TimeStamp);
}; 

inline Records::Records(void)
: Message(midi::NOTE_ON, 0, NoteId, 127, 0)
{
}

inline Records::Records(unsigned char Command, unsigned char Channel,
            unsigned char Data1, unsigned char Data2, 
            DWORD TimeStamp)
: Message(Command, Channel, Data1, Data2, TimeStamp)
{
}

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