我如何定位自定义对话框在特定的坐标？ [英] How Do I Position Custom Dialog at specific Coordinate?

问题描述

我是小白Android开发，我试图找出如何显示在特定的NewQuickAction3D弹出的对话框中查看坐标。我与整合这个弹出窗口教程。从本质上讲，我想用弹出的对话框中显示，其中用户触摸而不是使用InfoView的在画布上绘画的数据目前，弹出式窗口，在顶部和放大器;我固定它的视图的中心。我怎样才能使它显示特定的坐标？任何帮助是极大的AP preciated。

我的code

 公共无效updateMsg（字符串t_info，浮t_x，浮t_y，诠释T_C）{
     infoView.updateInfo（t_info，t_x，t_y，T_C）; // Infoview中油漆中，在一个特定的坐标
     quickAction.show（InfoView的）; //我如何使用t_x＆放大器; t_y而不只是协调锚固的InfoView这里
 

修改

 公共无效updateMsg（字符串t_info，浮t_x，浮t_y，诠释T_C）{
     infoView.updateInfo（t_info，t_x，t_y，T_C）;
     WindowManager.LayoutParams wmlp = quickAction.getWindow（）的getAttributes（）。 //错误及彼窗口属性
     wmlp.gravity = Gravity.TOP | Gravity.LEFT;
         wmlp.x = 100; // x位置
         wmlp.y = 100; // y位置
     quickAction.show（InfoView的）;
}
 

解决方案

覆盖您的视图onTouch（）

AlertDialog对话框;

  @覆盖
公共布尔onTouchEvent（MotionEvent事件）{
浮X = event.getX（）;
浮Y = event.getY（）;开关（event.getAction（））{
    案例MotionEvent.ACTION_DOWN：        的ShowDialog（）; //显示对话框
        打破;
    案例MotionEvent.ACTION_MOVE：
        如果（对话！= NULL）
          dialog.dismiss（）;
         // 做一点事
        打破;
    案例MotionEvent.ACTION_UP：
        //做somethig
        打破;
}
返回true;
}
 公共无效的ShowDialog（）
  {         AlertDialog.Builder建设者=新AlertDialog.Builder（FingerPaintActivity.this）;
         对话框= builder.create（）;
         dialog.setTitle（我的对话）;
         dialog.requestWindowFeature（Window.FEATURE_NO_TITLE）;
         WindowManager.LayoutParams wmlp = dialog.getWindow（）的getAttributes（）。
     wmlp.gravity = Gravity.TOP | Gravity.LEFT;
         wmlp.x = 100; // x位置
         wmlp.y = 100; // y位置
     dialog.show（）;
  }
 

即使绘制用户触摸屏幕，然后还显示对话框。因此解雇移动对话框中。

I'm a noob to android development and I am trying to figure out how to display the NewQuickAction3D popup dialog at a specific coordinate in a view. I am integrating the popup with this tutorial. Essentially, I want to use the popup dialog to display data where the users touch instead painting on the canvas using "infoview" Currently, the popup displays at the top&center of the view that I anchor it to. How can i make it display a particular coordinate? Any help is greatly appreciated.

MY CODE

public void updateMsg(String t_info, float t_x, float t_y, int t_c){
     infoView.updateInfo(t_info, t_x, t_y, t_c); //Infoview paints to on a specific coordinate
     quickAction.show(infoView); //How do I use the t_x & t_y coordinates here instead of just anchoring infoview

EDIT

public void updateMsg(String t_info, float t_x, float t_y, int t_c){
     infoView.updateInfo(t_info, t_x, t_y, t_c);
     WindowManager.LayoutParams wmlp = quickAction.getWindow().getAttributes(); //Error here getting window attributes
     wmlp.gravity = Gravity.TOP | Gravity.LEFT;
         wmlp.x = 100;   //x position
         wmlp.y = 100;   //y position
     quickAction.show(infoView);
}

解决方案

Override onTouch() of your view

AlertDialog dialog;

@Override
public boolean onTouchEvent(MotionEvent event) {
float x = event.getX();
float y = event.getY();

switch (event.getAction()) {
    case MotionEvent.ACTION_DOWN:

        showDialog();  // display dialog
        break;
    case MotionEvent.ACTION_MOVE:
        if(dialog!=null)
          dialog.dismiss(); 
         // do something
        break;
    case MotionEvent.ACTION_UP:
        // do somethig
        break;
}
return true;
} 
 public void showDialog()
  {

         AlertDialog.Builder builder = new AlertDialog.Builder(FingerPaintActivity.this);
         dialog = builder.create();
         dialog.setTitle("my dialog");
         dialog.requestWindowFeature(Window.FEATURE_NO_TITLE);
         WindowManager.LayoutParams wmlp = dialog.getWindow().getAttributes();
     wmlp.gravity = Gravity.TOP | Gravity.LEFT;
         wmlp.x = 100;   //x position
         wmlp.y = 100;   //y position
     dialog.show();
  }

Even to draw user touches the screen then also dialog is displayed. so dismiss dialog in on move.

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