关于C#图像计算 [英] About C# Image calculation

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本文介绍了关于C#图像计算的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

亲爱的Somewho:

我遇到有关C#语言的C#图片问题.
我正在尝试为我的学生做一些有关图片计算的程序.
像下面的例子

Dear Somewho:

I got a problem about C# image about C# language.
I am trying to do some program about picture calculation for my student.
example like the following

private void button2_Click(object sender, EventArgs e)
       {
           Bitmap b = pictureBox1.Image as Bitmap;
           if (b == null)
           {
               MessageBox.Show("Input Image");
               return;
           }

           int width = b.Width;
           int height = b.Height;

           // Lock Bitmap memory address
           BitmapData bd = b.LockBits(new Rectangle(0, 0, width, height),
           ImageLockMode.ReadOnly, PixelFormat.Format24bppRgb);
           int stride = bd.Stride;

           //Scan Image 
           IntPtr imgptr = bd.Scan0;

           //counting Bytes
           int widthByte = width * 3;

           //Counting Padding bytes 
           int skipByte = stride - widthByte;
           int[, ,] rgbData = new int[width, height, 3];

           #region Read RGB
           unsafe
           {
               byte* p = (byte*)(void*)imgptr;
               for (int j = 0; j < height; j++)
               {
                   for (int i = 0; i < width; i++)
                   {
                       rgbData[i, j, 2] = p[0]; // Blue
                       p++;
                       rgbData[i, j, 1] = p[0]; // Green
                       p++;
                       rgbData[i, j, 0] = p[0]; // Red
                       p++;
                   }
                   p += skipByte;              //Skip Padding bytes
               }
           }
           #endregion

           #region Gray Scalar
           unsafe
           {
               imgptr = bd.Scan0;
               byte* p = (byte*)(void*)imgptr;
               for (int j = 0; j < height; j++)
               {
                   for (int i = 0; i < width; i++)
                   {
                       int gray = (rgbData[i, j, 0] + rgbData[i, j, 1] + 
                                   rgbData[i, j, 2]) / 3;
                       p[0] = (byte)gray; // Blue to Gray
                       p++;
                       p[0] = (byte)gray; // Green to Gray
                       p++;
                       p[0] = (byte)gray; // Red Gray
                       p++;
                   }
                   p += skipByte; //Skip Padding bytes
               }
           }
           #endregion
           b.UnlockBits(bd);
           Refresh();
       }



问题是我不知道如何计算像素位置.
例如:
要在该图片上输入一张为三角形或正方形图形的图片.
如何获得关于正方形[x1,y1] suqare [x2,y2]正方形[x3,y3]正方形[x4,y4]的正方形提示关节位置
因此很难使用g.drawline(x,y)来圈出4边的正方形长度.
如果可能的话,您介意告诉我如何获得方形4尖头位置的位置吗?
最好的问候,.



The problem is I don''t know how to calculate pixel position.
For example:
To input one picture which is a triangle or square graphics on this picture.
How can I get this square tips joint position about square [x1,y1] suqare[x2,y2] square[x3,y3] square[x4,y4]
so it''s hard to use g.drawline(x,y) to circulate out the square 4 side length.
If it is possible, would you mind to tell me about how to get the position for square 4 tips position?
Best Regards,.

推荐答案

在图片上显示形状很容易:
在设计器中创建一个PictureBox并将其添加到表单中.
给它一个Image属性.
处理绘画事件:
Showing shapes on a picture is easy:
Create a PictureBox in the designer and add it to your form.
Give it an Image property.
Handle the Paint event:
private void myPictureBox_Paint(object sender, PaintEventArgs e)
    {
    Graphics g = e.Graphics;
    g.FillRectangle(Brushes.Yellow, new Rectangle(20, 20, 30, 30));
    GraphicsPath p = new GraphicsPath();
    p.AddLines(new Point[] { new Point(50, 50), new Point(30, 80), new Point(80, 80), new Point(50, 50) });
    g.FillPath(Brushes.Red, p);
    }


这将在图像上绘制一个简单的黄色正方形和一个红色三角形.
确定尺寸是基本的几何形状,并且非常简单,但是要取决于您的形状.


This will draw a simple yellow square and a red triangle on your image.
Working out the sizes is basic geometry, and pretty simple, but will depend on your shape.


这篇关于关于C#图像计算的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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