如何编写获取指针数组的Callback函数? [英] How do I write a Callback function that gets an array of pointers?

问题描述

我正在尝试实现一个回调函数，该函数将返回一个指针数组.这是我的代码，但我不断收到错误消息.有谁知道返回指针数组的回调函数的正确语法?
代码:

Hi,
I am trying to implement a Callback function that would return an Array of pointers. Here is my code, but I keep getting an error message. Does anyone know the correct syntax for a callback function that returns an array of pointers?
code:

//The original array is here:
__declspec(dllexport) bot_movestate_t *botmovestates[MAX_CLIENTS+1];
__declspec(dllexport) struct bot_movestate_s **Getbotmovestates( void )
{
	return botmovestates;
}

struct bot_movestate_s *ai_main_botmovestates[MAX_CLIENTS+1];
typedef struct bot_movestate_s **(* fGetbotmovestates_t)( void );
struct bot_movestate_s **fGetbotmovestates( fGetbotmovestates_t pfGetbotmovestates ){
	return pfGetbotmovestates();
}

//sm func
void smfunc()
{
	fGetbotmovestates_t pfGetbotmovestates;
	HMODULE hLib;
	
/////////////////////////////

	hLib = LoadLibrary(TEXT("smdll.dll"));
		if (hLib == NULL) {
		//Module not found, permission denied, ...
		return; //inform caller of error
	}

	pfGetbotmovestates = (fGetbotmovestates_t)GetProcAddress(hLib, TEXT("Getbotmovestates"));
	if ( pfGetbotmovestates == NULL) {
		return;
	}

	ai_main_botmovestates = fGetbotmovestates(pfGetbotmovestates);//error C2106: ''='' : left operand must be l-value

/////////////////////////////

}

//error
error C2106: ''='' : left operand must be l-value

推荐答案

您已将ai_main_botmovestates定义为指针数组而不是指针，因此如果不使用索引就无法为其分配任何内容.将其声明更改为:

You have defined ai_main_botmovestates as an array of pointers rather than a pointer, so you cannot assign anything to it without using an index. Change its declaration to:

struct bot_movestate_s **ai_main_botmovestates;

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