我已经创建了一个返回列表的函数. [英] I have Created a function which return a list.

问题描述

大家好，

我创建了一个返回IList的方法，

列表返回一行，
所以，我想在不同的标签中设置列表值...

这是我的代码.

Hello ALL,

I have created a method which return a IList,

List return a one row,
So ,I want to set the list value in different label...

Here is my code..

if (mediationinfolist.Count >= 1)
       {
           mediationinfo.Mediationinfolist = mediationinfolist;
       }

       for (int i = 1; i <= mediationinfo.Mediationinfolist.Count; i++)
       {
           lblMediationDate.Text = Functions.GetDate(mediationinfo.Mediationinfolist[i].MediationDate, 7);

}

它显示索引超出范围异常.

请给我解决方案..

}

it show index out of range exception.

please give me solution..

推荐答案

以
运行循环 for (int i = 0; i <= mediationinfo.Mediationinfolist.Count-1; i++).

将来，请尝试调试代码，确保可以自己找到解决方案.

Run your loop as
for (int i = 0; i <= mediationinfo.Mediationinfolist.Count-1; i++).

In the future, try and debug your code and I''m sure you will be able to find the solution yourself.

请注意以下有关数组，列表和索引值的内容
1. 索引始终从0而不是1开始.
2.用 0 计数计数器，然后循环直到 count-1

首先阅读理论部分，然后进行编码，这是基本的事情.
编程愉快.

Note following points about Array, list and index values
1. Index start with always 0 not 1.
2. Srart counter with 0 and loop until count-1

Read theory part first and then go for coding this is basic thing.
Happy programming.

按照另一位专家的建议，我尝试将i++更改为++i，令我惊讶的是，发现它的运行速度相当快(对于循环体，当然).另外，有人说<"条件更快.我还将改善命名；一个字符的名称确实很糟糕.因此，要改善显示我的Abhinav的解决方案(我认为是正确的)，请执行以下操作:

Following the advice by one other expert, I tried to change i++ to ++i and, to my surprise, found that it works considerably faster (for small footprint in the loop body, of course). Also, some say the ''<'' condition is faster. I''ll also improve naming; one-character names are really bad. So to improve the solution shown my Abhinav (which I credit as correct), do:

for (int index = 0; index < mediationInfo.MediationInfoList.Count; index++) {/*...*/}

使用调试器！

祝你好运，

—SA

Use the debugger!

Good luck,

—SA

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