输入字符时Convert.ToInt32(Readline())给出错误 [英] Convert.ToInt32(Readline()) gives error when a character is entered

问题描述

请看下面的代码

Hi, Look at the Following code

char c = 'a';
a=Convert.ToInt32(c);
Console.WriteLine("hi" + a);//displays output:- Hi97
a=Convert.ToInt32(Console.ReadLine());//Gives complie time error(throws an exception) if I enter 'a'(a only without quotes) on screen.

为什么Convert.ToInt32()在两种情况下的行为会有所不同.

Why the Convert.ToInt32() is behaving differently in 2 situations.

推荐答案

在第一种情况下，您定义了一个字符，添加后将其转换为ascii值(97)到字符串.

当您使用Console.ReadLine()方法时，该方法不返回字符而是字符串.因此，如果此字符串包含字符，则无法将其转换为整数.

In the first case you have defined a single character which is converted to ascii value (97) when added to the string.

When you use Console.ReadLine() method, the method doesn''t return a character but a string. So this string cannot be converted to integer if it contains characters.

请参见^

因为在ASCII字符集中"a"的等效项是97.在这种情况下，使用Int32.TryParse方法会更好.请参阅链接以供参考:
http://msdn.microsoft.com/en-us/library/f02979c7.aspx [ ^ ]

问候，
爱德华

Because the equivalent of ''a'' in ASCII character set is 97. Using Int32.TryParse method would be better in this case. See the link for your reference:
http://msdn.microsoft.com/en-us/library/f02979c7.aspx[^]

Regards,
Eduard

这篇关于输入字符时Convert.ToInt32(Readline())给出错误的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！