将Listview数据绑定到列表 [英] Databinding Listview to List

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本文介绍了将Listview数据绑定到列表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个包含多列的listview控件.每列均由List<t>对象填充,该对象从数据库查询中接收项目.根据特定列值的内容为行着色的行.我想知道如何将List<t>绑定到列表视图?这是最有效的方法吗?我应该改用dataTable吗?如果是这样,我该如何绑定它并根据列/行的内容为列着色.

这是我的代码示例:

I have a listview control with multiple columns. Each column is populated by a List<t> object that receives it items from a DB query. rows colored according to the contents of specific column values. I wanted to know how can I bind the List<t> to the listview? Is this the most efficient to go about this? Should I be using a dataTable instead? If so how do I bind it and color the columns according to column/row contents.

Here''s an example of my code:

class Data
{
  public List<string> info = new List<string>();
  public List<string> info2 = new List<string>();

  public void GetData()
  {
     // create ADO.NET objects i.e. connection, command, dataReader, etc...
     // connect to database 
     // execute query
    
    SqlDataReader rdr = sqlCmd.ExecuteReader();
    
    while(rdr.Read())
    {
      info.Add(rdr["data1"]);
      info2.Add(rdr["data2"]);
    }
  }

// Windows Form section

Data dat = new Data();

public void button1_click(object sender, eventargs e)
{
   dat.GetData();
  
   for(int i = 0; i < dat.info.Count; i++)
   {
      string s = dat.info[i];
      string s2 = dat.info2[i];
     
      listview.Items[i].Add(dat.info[i]));
      listview.Items[i].SubItems.Add(dat.info2[i]);

     if(s == "xyz")
     {
       listview.Items[i].BackColor = Color.Green;
     }

     if(s2 == "rst")
     {
       listview.Items[i].Backcolor = Color.Red;
     }
   }
}


将listview绑定到数据表或绑定列表是否更有效,这样我就不必遍历每一行?


Wouldn''t it be more efficient to bind the listview to a datatable or bindinglist so that way i wouldn''t have to iterate though each row? how do I create a customListview for this and how would I go about the coloring scheme?

推荐答案

值得一看的是
It is worth to see this[^] CodeProject answer.


尝试
绑定ListView的数据 [
Try
Data binding a ListView[^]


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